I have been trying for over an hour now to get the numeric value for "HalfLifeN" from the code in the screenshot below. Not to mention mathematica simplifies $e^{ln(x)}$ to $ 2^x$, which I don't want it to do.

I can work through this by hand, but I would really prefer not to. Is there any way I can access the values of "HalfLifeN" even though they are internal to the nlmf function?

Thank you.

enter image description here

My temporary workaround was to use a different variable not dependent of Log2, and then copy and past it to solve for the half life. enter image description here

  • 4
    $\begingroup$ Please provide code instead of screenshots. This will make dealing with your input much easier. $\endgroup$
    – Jinxed
    Commented Apr 23, 2015 at 8:38

1 Answer 1

Flatten[#["BestFitParameters"][[All, 2]] & /@ {data1Fit, data2Fit, data3Fit}]


{HalfLife1, HalfLife2, HalfLife3 } /.
   Flatten[ #["BestFitParameters"] &/@ {data1Fit, data2Fit, data3Fit}]

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