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Note: This might be trivial for many of the users but i am new to mathematica so i don't know!!!

Question: Suppose i have three list of data as follows:

List1 = {{a11}, {a21, a22}, {a31, a32, a33}};
List2 = {{b11}, {b21, b22}, {b31, b32, b33}};
List3 = {{c11}, {c21, c22}, {c31, c32, c33}};

Here all three list have the same length, i.e. $Length[{List}_1]=Length[{List}_2]=Length[{List}_3]$

Can someone write me a simple fast function $f$ that can do the following:

{{a11, b11, c11}, {a21, b21, c21}, {a31, b31, c31}, {a22, b22, 
 c22}, {a32, b32, c32}, {a33, b33, c33}}
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    $\begingroup$ This looks very much like Mathematica code copied as LaTeX. I strongly suggest refraining from using subscripts in the classical manner in Mathematica. All sorts of issues are bound to come up. $\endgroup$ – LLlAMnYP Apr 17 '15 at 21:30
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Edit:

f = Flatten[{##}, {3, 2}] &

ref: Flatten command: matrix as second argument

Old:

f[lists__]:=Transpose[Flatten/@ {lists}]
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