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I have one surface for which I have an analytical solution, and another represented by a list of 3D points. My question is: how can I plot the part of one that lies outside the other?

The first surface:

R = 1;
Ω = Disk[{0, 0}, {R, R}];
θ = 1;
G = 1;
Φ = 1/2 G θ R^2 (1 - x^2/R^2 - y^2/R^2);
Plot3D[Φ, {x, y} ∈ Ω, 
  PlotStyle -> None, 
  PlotTheme -> "Detailed", Mesh -> {25}, 
  AxesLabel -> {"x", "y", "ϕ(x,y)"}, 
  LabelStyle -> Directive[FontFamily -> "Courier New"]]

enter image description here

The second surface:

circle = 
  {{(2 - Sqrt[3])/2, 0.5, 0}, {0, 1, 0}, 
   {(2 - Sqrt[3])/2, 1.5, 0}, {0.5, (2 - Sqrt[3])/2, 0}, 
   {0.5, 0.5, 0.3774047358083551`}, {0.5, 1, 0.4599364905389034`}, 
   {0.5, 1.5, 0.3774047358083551`}, {0.5, (2 + Sqrt[3])/2, 0}, 
   {1, 0.`, 0}, {1, 0.5, 0.4599364905389034`}, 
   {1, 1, 0.5849364905389033`}, {1, 1.5, 0.4599364905389034`}, 
   {1, 2, 0}, {1.5, (2 - Sqrt[3])/2, 0}, 
   {1.5, 0.5, 0.3774047358083551`}, {1.5, 1, 0.4599364905389034`}, 
   {1.5, 1.5, 0.3774047358083551`}, {1.5, (2 + Sqrt[3])/2, 0}, 
   {(2 + Sqrt[3])/2, 0.5, 0}, {2, 1, 0}, {(2 + Sqrt[3])/2, 1.5, 0}}
ListPlot3D[circle, 
  PlotStyle -> None, 
  PlotTheme -> "Detailed", 
  Mesh -> {3, 3}, 
  AxesLabel -> {"x", "y", "ϕ(x,y)"}, 
  InterpolationOrder -> 2, 
  LabelStyle -> Directive[FontFamily -> "Courier New"]]

enter image description here

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9
  • $\begingroup$ What is kor ? $\endgroup$
    – ciao
    Apr 4, 2015 at 6:58
  • $\begingroup$ @rasher sorry, i corrected, kor=circle $\endgroup$
    – wlkyr
    Apr 4, 2015 at 7:00
  • $\begingroup$ I don't understand in what sense "subtract" or "withdrawn." The domains are different, so do you want to subtract the smaller circle from the greater, leaving a hole? Do you want to subtract the ordinates over the intersection of the domains? Likewise, do you want an interpolation of the "another" and subtract it from Φ over the intersection of the domains? Something else, perhaps? $\endgroup$
    – Michael E2
    Apr 4, 2015 at 12:07
  • $\begingroup$ @MichaelE2 I want to substract the smaller circle from the greater, leaving a hole, like you wrote firstly. And that way get the difference between the two circle. The domain is R=1 at the circles. (Both of them) Then I want to present it on a circle domain with interpolation. $\endgroup$
    – wlkyr
    Apr 4, 2015 at 13:44
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    – Michael E2
    Apr 4, 2015 at 21:36

1 Answer 1

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I think this is what you mean:

Plot3D[Φ, {x, y} ∈ 
  RegionDifference[DiscretizeRegion@Ω, 
   ConvexHullMesh[circle[[All, 1 ;; 2]]]], PlotStyle -> None, 
 PlotTheme -> "Detailed", Mesh -> {25}, 
 AxesLabel -> {"x", "y", "ϕ(x,y)"}, 
 LabelStyle -> Directive[FontFamily -> "Courier New"]]

Mathematica graphics

But perhaps I subtracted them in the wrong order, or plotted the wrong function. In which case, maybe this:

ListPlot3D[circle, PlotStyle -> None, PlotTheme -> "Detailed", 
 Mesh -> {3, 3}, AxesLabel -> {"x", "y", "ϕ(x,y)"}, 
 InterpolationOrder -> 2, 
 LabelStyle -> Directive[FontFamily -> "Courier New"],
 RegionFunction -> 
  Function[{x, y}, {x, y} ∉ Ω]
 ]

Mathematica graphics

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