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I am new in the Mathematica community and I have a probably easy question for you regarding how to sort a dataset as the following so that I have sorted the values in the fist row descending from 44 in the first line down to 3 in the last line.

dataset = Dataset[{
  <|"a" -> 6, "b" -> "x", "c" -> {1}|>, 
  <|"a" -> 8, "b" -> "y", "c" -> {2, 3}|>, 
  <|"a" -> 44, "b" -> "z", "c" -> {3}|>, 
  <|"a" -> 4, "b" -> "x", "c" -> {4, 5}|>, 
  <|"a" -> 5, "b" -> "y", "c" -> {5, 6, 7}|>, 
  <|"a" -> 3, "b" -> "z", "c" -> {}|>}]
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  • 2
    $\begingroup$ dataset[SortBy[-#a &]]. $\endgroup$
    – Leonid Shifrin
    Mar 20, 2015 at 18:38
  • 1
    $\begingroup$ ..... or dataset[SortBy[a]][Reverse] ;-) $\endgroup$
    – mgamer
    Mar 20, 2015 at 18:42
  • $\begingroup$ Perfect!! Thank you very much for the quick response!! $\endgroup$
    – Hans Meier
    Mar 20, 2015 at 18:52
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    $\begingroup$ dataset[SortBy[a] /* Reverse] $\endgroup$
    – alancalvitti
    Mar 20, 2015 at 20:07
  • 1
    $\begingroup$ Reverse @ Sort@ ds $\endgroup$
    – m_goldberg
    Mar 21, 2015 at 3:08

1 Answer 1

Reset to default
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Let's gather all the answers in the comments here.

dataset[SortBy[-#a &]]
dataset[SortBy["a"]][Reverse]
dataset[SortBy["a"] /* Reverse]
Reverse @ Sort @ dataset
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1
  • $\begingroup$ I corrected SortBy[a] to SortBy["a"]. The former does produce the correct result, but that's just a coincidence. It's in fact equivalent to a simple Sort and the symbol a makes no difference, one could write b or c and it wouldn't change the result. $\endgroup$
    – Szabolcs
    May 17, 2015 at 17:47

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