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Consider I have a power series which is function of $x$. A part of this expression is bounded when $x->\infty$, some remainder is on the other hand divergent when $x$ goes to infinity. What is the simplest way to extract out of my expression only the bounded part?

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  • $\begingroup$ I believe you're talking about a power Series. Otherwise you can always manipulate any expression to have as many "divergent" parts as you want cancelling out themselves when you add them up $\endgroup$ – Dr. belisarius Mar 5 '15 at 22:05
  • $\begingroup$ Sure, sorry for the misunderstanding. $\endgroup$ – usumdelphini Mar 5 '15 at 22:07
  • $\begingroup$ One place to start might be Series[func, {x,Infinity,1}]. If the divergent part is of polynomial or similar growth this might capture it. $\endgroup$ – Daniel Lichtblau Mar 5 '15 at 23:59

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