# Showing an output without square brackets

Suppose that an output is

which could be obtained from, for example,

D[f[x, y, z], x] / D[h[x, y, z], x]


I'm looking for a way to show it without the square brackets.

Currently I do that by copying the output to a text editor and removing, in this case, [x, y, z] with the Replace command, then copying the expression back to Mathematica. How to do this in Mathematica itself automatically?

• Please post your code in a readable form (e.g. InputForm). – Yves Klett Jan 23 '15 at 14:29
• A more readable form added. – Taiki Jan 23 '15 at 14:34
• Not sure what the downvote is for... – Yves Klett Jan 23 '15 at 17:17

Select the cell containing your output, then choose TraditionaForm from the Convert To submenu of the Cell menu. The cell will then show

### Update

Perhaps this is what you are looking for:

(f^(1,0,0))[x, y, z]/(h^(1,0,0))[x, y, z] /. h_[x, y, z] -> h


• Thank you. I have a very large expression and adding /. h_[...] -> h really helps. Now I feel stupid for asking the question in the first place. :-D – Taiki Jan 23 '15 at 15:02

A look at the FullForm motivates e.g. this:

der = Derivative[1, 0, 0][f][x, y, z]/Derivative[1, 0, 0][h][x, y, z];

der /. Derivative[a___][b___][c___] :> Derivative[a][b]


• This is quite elegant, but it does change the meaning of the actual expression and not just its appearance. For instance, Derivative[1][Sin][x] yields Cos[x], whereas Derivative[1][Sin] yields Cos[#1] &. Whether this matters depends on the use that the author of the question intends. – bbgodfrey Jan 23 '15 at 15:00
• @bbgodfrey agreed on the non-equivalence of the expressions and the not-yet clear intention of the OP. – Yves Klett Jan 23 '15 at 15:09
• What's not clear about my intention? – Taiki Jan 23 '15 at 15:11
• @Taiki I was not sure if you just wanted the typeset expression or something related to the original expression, but the formulation of your goal is clear :D – Yves Klett Jan 23 '15 at 17:16