Making table of matrix product and efficiency

Question

I want to make a table in which each element is a matrix product:

<< Developer`
n = 2;
m = 6;

matrix = Map[ToPackedArray[#] &, Table[Sin[1.0*i*j], {i, 1, m}, {j, 1, n}, {k, 1, n}]];

vector = {IdentityMatrix[n][[1]]}\[Transpose];

Do[Flatten[Table[ #1\[ConjugateTranspose].(matrix[[#2]].#1) &[vector, i], {i, 1, m}]], {ite, 1, 2*10^5}] // AbsoluteTiming
(*{7.430010, Null}*)

In the code above there are two important parts:

First part = Choosing one matrix from the lists of matrices matrix and multiply it by vector.

Second part = Multiplying vector\[ConjugateTranspose] by the result of the first part.

I thought if I convert matrix[[#2]].#1, the first part, into one matrix multiplication, it would be more efficient as instead of many multiplications I calculate all of them in one go:

matrix2 = ToPackedArray[Flatten[Table[matrix[[i]]\[Transpose], {i, 1, m}], 1]];

matrix2 is the desired matrix to do the next step. If you use matrix//MatrixForm, then both the matrices look like each other.

Do[x = matrix2.vector; Flatten[Table[ #1\[ConjugateTranspose].(x[[#2 ;; #2 + n - 1,All]]) &[vector, i], {i, 1, n*m, n}]], {ite, 1, 2*10^5}] // AbsoluteTiming
(*{9.080013, Null}*)

I had to still choose different parts of (matrix2.#1),first part, to multiply that part with #1\[ConjugateTranspose],second part.

As you see although I calculate all the matrix multiplications in the first part at once, it is slower. I thought it might be because of this part of code [[#2 ;; #2 + n - 1, All]] in which I had to choose different parts of the result. I tried:

Do[x = matrix2.vector; Flatten[Table[ (x[[#1 ;; #1 + n - 1, All]]) &[i], {i, 1, n*m, n}]], {ite, 1, 2*10^5}] // AbsoluteTiming
(*{5.290007, Null}*)

Do[Flatten[Table[ (matrix[[#2]].#1) &[vector, i], {i, 1, m}]], {ite, 1, 2*10^5}] // AbsoluteTiming
(*{4.630007, Null}*)

At each iteration for matrix2 I just do the calculation once but for that of matrix at each iteration there are 6 multiplications. In the below I remove the table for matrix2 and replace it with Do for matrix:

Do[x = matrix2.vector, {ite, 1, 2*10^5}] // AbsoluteTiming
(*{0.240000, Null}*)

Do[ Do[(matrix[[#2]].#1) &[vector, i], {i, 1, m}], {ite, 1, 2*10^5}] // AbsoluteTiming
(*{2.620004, Null}*)

Now the calculations for matrix2 are faster. Thus, I believe that choosing parts of matrix2.vector causes the calculation gets slower.

How can I overcome this bottleneck? How can I choose parts of a matrix faster?

Answer 1

You can increase the performance by transposing your matrix and using Dot without explicit [[...]]

<< Developer`
n = 2;
m = 6;

matrix = Table[Sin[1.0*i*j], {i, m}, {j, n}, {k, n}];
matrix3 = ToPackedArray@Transpose@matrix;

vector = N@Transpose@{IdentityMatrix[n]};
vectorHC = ConjugateTranspose@vector;

Flatten[vectorHC.matrix3.vector, {{1, 3, 2, 4, 5}}] == 
 Flatten@Table[#1\[ConjugateTranspose].(matrix[[#2]].#1) &[vector, i], {i, 1, m}]
(* True *)

Do[Flatten[vectorHC.matrix3.vector, {{1, 3, 2, 4, 5}}], {ite, 10^5}] // AbsoluteTiming
(* {0.894130, Null} *)

Do[Flatten[Table[#1\[ConjugateTranspose].(matrix[[#2]].#1) &[vector, i], {i, m}]], 
  {ite, 10^5}] // AbsoluteTiming
(* {8.979821, Null} *)

Converting vector to a floating-point array (N[...]) also increase the performance a bit.