I need to plot the following curve in a triangular (ternary) plot: $$|x_{BB}-x_{AA}|=(\sigma_c-2x_{AB}+1)^{\gamma}, \qquad (1)$$ subjected to the condition (this condition must satisfy for a ternary plot) $$x_{AA}+x_{AB}+x_{BB}=1, \qquad (2)$$
where $\sigma_c$ is a positive constant, say 1, and $\gamma=0.35$.
My attempt is to express $x_{AB}$ in terms of the other two variables from the equation (2) and substitute the resulting expression in (1), then I obtain the following:
Abs[b - a] == (2 - 2 (1 - a - b))^0.35
Questions:
a) Is this expression equivalent to the equations (1) and (2)?
b) How do I plot the curve (1) subjected to (2) in a ternary form?