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How can I plot the frequency of list items such as?: {62, 62, 62, 64, 64, 64, 64, 64, 64, 66, 66, 66, 66, 67, 67, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 91, 91, 91, 91, 91, 91, 94, 95, 95, 95, 95, 100, 100, 100, 100, 100, 100}

Also, would it be possible to have the list replace the item with a name? For example, instead of showing that 62 appears 3 times, show that "Joe" has 3 matches in the list?

I apologize if this is a trivial matter; I've been searching for a few days.

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  • $\begingroup$ Possible duplicate: (9801) $\endgroup$ – Mr.Wizard♦ Sep 20 '14 at 9:16
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data1 = {62, 62, 62, 64, 64, 64, 64, 64, 64, 66, 66, 66, 66, 67, 67, 
   82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 91, 91, 91, 91, 91,
    91, 94, 95, 95, 95, 95, 100, 100, 100, 100, 100, 100};

names = {62 -> "Joe", 64 -> "Sharon", 66 -> "Bill",
   67 -> "Kelly", 82 -> "Jim", 91 -> "Sue",
   94 -> "Mike", 95 -> "Alice", 100 -> "Bob"};

freq1 = Tally[data1]

{{62, 3}, {64, 6}, {66, 4}, {67, 2}, {82, 12}, {91, 6}, {94, 1}, {95, 4}, {100, 6}}

ListPlot[freq1, Filling -> Axis]

enter image description here

data2 = data1 /. names;

freq2 = Tally[data2]

{{"Joe", 3}, {"Sharon", 6}, {"Bill", 4}, {"Kelly", 2}, {"Jim", 12}, {"Sue", 6}, {"Mike", 1}, {"Alice", 4}, {"Bob", 6}}

StringForm["`1` has `2` matches", ##] & @@@ freq2

enter image description here

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  • $\begingroup$ I recommend that you remove the line freq2 = freq1 /. names as this could easily lead to error as it will replaces counts as well as items. +1 however since you give the better way immediately below. $\endgroup$ – Mr.Wizard♦ Sep 20 '14 at 6:59
  • $\begingroup$ @Mr.Wizard - Modified per your recommendation. Thanks. $\endgroup$ – Bob Hanlon Sep 21 '14 at 12:25
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Using:

data1 = {62, 62, 62, 64, 64, 64, 64, 64, 64, 66, 66, 66, 66, 67, 67, 
   82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 82, 91, 91, 91, 91, 91,
    91, 94, 95, 95, 95, 95, 100, 100, 100, 100, 100, 100};

names = {62 -> "Joe", 64 -> "Sharon", 66 -> "Bill", 67 -> "Kelly", 
   82 -> "Jim", 91 -> "Sue", 94 -> "Mike", 95 -> "Alice", 
   100 -> "Bob"};

You can useBarChart:

BarChart[Labeled[#2, #1 /. names] & @@@ Tally[data1]]

enter image description here

Or 

Needs["StatisticalPlots`"]
ParetoPlot[data1, ChartLabels -> (SortBy[Tally[data1], -#[[2]]&][[All, 1]]/. names), 
 LabelingFunction -> (Placed[
     Panel[NumberForm[N@#1, 2], FrameMargins -> 0], Above] &)]

enter image description here

You can use StringTemplate for the textual aim,e.g.

s = StringTemplate["<*`1`/.names*> has `2` matches.\n"];
StringJoin @@ (TemplateApply[s, #] & /@ Tally[data1])

produces:

Joe has 3 matches. Sharon has 6 matches. Bill has 4 matches. Kelly has 2 matches. Jim has 12 matches. Sue has 6 matches. Mike has 1 matches. Alice has 4 matches. Bob has 6 matches.

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For the plotting part of your question:

ListPlot[Tally[lst], Filling -> Axis]
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