# Assign output of solve to variables [duplicate]

I have this input:

Solve[x^2 + 3 x + 2 == 0, x]


which gives this output:

{{x -> -2}, {x -> -1}}


I want the first x to be named x1 and the second x to be named x2 without having to copy the value and doing x1=-2 manually and x2=-1

## marked as duplicate by Artes, eldo, Dr. belisarius, Sjoerd C. de Vries, JensSep 20 '14 at 0:08

{x1, x2} = x /. Solve[x^2 + 3 x + 2 == 0, x]

{-2, -1}

• loved it! Thanks! – Onizuka Sep 19 '14 at 17:43
{x1, x2} = Last @@@ Solve[x^2 + 3 x + 2 == 0, x]
(* {-2, -1} *)


or

{x1, x2} = Solve[x^2 + 3 x + 2 == 0, x][[All,1,-1]]
(* {-2, -1} *)


or

sol = Solve[x^2 + 3 x + 2 == 0, x];
sol[[All, 0]] = Last;
{x1, x2} = sol
(* {-2, -1} *)


Note: Since this question has a much simpler structure than the question linked by Artes, these tricks work for the current case (with a single-variable expression to be solved), but not for the more general case in the linked Q/A.

• Can't you see it's a duplicate? – Artes Sep 19 '14 at 20:18
• @Artes, -- now that i saw your comment -- yes. – kglr Sep 19 '14 at 20:35

A certain generalization using an indexed variable:

r = FindInstance[Sin[x] == Cos[x] && -10 < x < 10, x, Reals, 15] // Values // Flatten // N


{-5.49779, 7.06858, 0.785398, -8.63938, 3.92699, -2.35619}

Map[(x[#] = r[[#]]) &, Range @ Length @ r];

{x[1], x[2], x[3], x[4], x[5]}


{-5.49779, 7.06858, 0.785398, -8.63938, 3.92699, -2.35619}