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I need help in solving equation 15 and 16 either manually or in Mathematica to get the solution in terms of the incomplete gamma function. enter image description here

This is what Mathematica tells me. I can't understand what is the problem. enter image description here

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  • $\begingroup$ Welcome to Mathematica.SE. From experience I know that you are more likely to receive an answer if you demonstrate effort to solve this on your own, or request help with a specific method or idea. Questions that look like "do my homework for me" are usually ignored. $\endgroup$
    – Mr.Wizard
    Sep 14 '14 at 7:07
  • $\begingroup$ Actually i tried on mathematica and also manually but got stuck..just want to have hints how to proceed $\endgroup$ Sep 14 '14 at 7:10
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    $\begingroup$ I suggest you include what you tried. Understand I am not personally demanding this (actually I think showing failed attempts is not really desirable; see this), I am merely trying to help you get answers, and I know that many people will not answer unless effort it demonstrated, for better or worse. $\endgroup$
    – Mr.Wizard
    Sep 14 '14 at 7:15
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DSolve[e t''[e] + (1 - Pr/b^2 (1 + bs) + e) t'[e] == 0 &&  t[Pr/b^2] == 1 && t[0] == 0, t, e] 
                                                               // TraditionalForm // TeXForm

$$\left\{\left\{t\to \left(\{e\}\to \frac{\Gamma \left(\frac{(\text{bs}+1) \Pr }{b^2},0\right)-\Gamma \left(\frac{(\text{bs}+1) \Pr }{b^2},e\right)}{\Gamma \left(\frac{(\text{bs}+1) \Pr }{b^2},0\right)-\Gamma \left(\frac{(\text{bs}+1) \Pr }{b^2},\frac{\Pr }{b^2}\right)}\right)\right\}\right\}$$

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  • $\begingroup$ Any idea "what is the problem" with the OP's code? $\endgroup$
    – Michael E2
    Sep 14 '14 at 13:40
  • $\begingroup$ @MichaelE2 Which code ? :D. That's why I'm a strong believer in the need of the OP posting some code. You can't teach anything in situations like this one: just see and look how it's done $\endgroup$ Sep 14 '14 at 17:36
  • $\begingroup$ I agree about posting code. But since you retyped it, I thought you probably saw that there's no space between the ε and the θ in the picture of the OP's code. $\endgroup$
    – Michael E2
    Sep 14 '14 at 17:42
  • $\begingroup$ @MichaelE2 Nope, my sight and patience aren't up to the task $\endgroup$ Sep 14 '14 at 17:48

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