I want to draw the following picture in Mathematica as shown below with distinct color for each section.
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$\begingroup$ Well, did you try anything and, if yes, where did you get stuck? $\endgroup$ – acl Jul 16 '14 at 11:25
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1$\begingroup$ I used this code: Plot3D[-1/4 x^3, {x, -20, 20}, {y, 0, 30}, ColorFunction -> Function[{x}, Piecewise[{{Red, -20 <= x < -10}, {Orange, -10 <= x < 0}, {Yellow, 0 <= x <= 20}}]], PlotStyle -> Thick, ColorFunctionScaling -> False] $\endgroup$ – SKMohammadi Jul 16 '14 at 11:32
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Try using MeshShading:
Plot3D[
-(x - 12.5)^3,
{x, 0, 25},
{y, 0, 20},
MeshShading -> {Table[Hue[x], {x, 0, 1, 1/16}]}
]
The Table part generates sixteen different colors from the Hue color function. I did this because the image in this case had sixteen rows. If there are more rows than colors the colors will be reused cyclically.
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$\begingroup$ Thanks you. and about dotted grid lines in background? $\endgroup$ – SKMohammadi Jul 16 '14 at 12:13
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$\begingroup$ @MathMan I was away, it seems Mr.Wizard solved it in the meantime :) $\endgroup$ – C. E. Jul 16 '14 at 14:32
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Building on Pickett's answer with a few more Options:
pl = Plot3D[-(x - 12.5)^3, {x, 0, 25}, {y, 0, 20},
MeshShading -> {Table[Hue[x], {x, 0, 1, 1/16}]},
BoxRatios -> 1,
Boxed -> False,
FaceGrids -> {{0, 1, 0}, {-1, 0, 0}, {0, 0, -1}},
FaceGridsStyle -> Directive[Thick, Gray, Dotted]
]
It's not perfect but hopefully it points you in a useful direction.
An example for the legend was requested. One can use Inset to place a Graphics (or other) object in a 3D plot. As a rough illustration:
rec = Graphics[{Green, EdgeForm[Thick], Rectangle[{0, 0}, {50, 20}]},
ImageSize -> {50, 20}, PlotRangePadding -> 0];
lg = Framed[Row[{rec, Style["S", 18]}]];
Show[pl, Epilog -> Inset[lg, Scaled[{0.8, 0.8}]]]
answered Jul 16 '14 at 13:01
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$\begingroup$ I copied the wrong code for that particular graphic. Now corrected. Sorry for any confusion. $\endgroup$ – Mr.Wizard♦ Jul 16 '14 at 13:16
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$\begingroup$ @MathMan Which version of Mathematica are you using? $\endgroup$ – Mr.Wizard♦ Jul 16 '14 at 23:44
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