For this expression: $ (1 - Exp[-Sqrt[1+s] x])/(1+s)$
How to make the Inverse Laplace Transform analytically?
InverseLaplaceTransform[(1 - Exp[-Sqrt[1+s] x])/(1+s),s,t] does not directly give solution
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Sign up to join this communityFor this expression: $ (1 - Exp[-Sqrt[1+s] x])/(1+s)$
How to make the Inverse Laplace Transform analytically?
InverseLaplaceTransform[(1 - Exp[-Sqrt[1+s] x])/(1+s),s,t] does not directly give solution
I'm not a mathematician so this may be "smoke and mirrors."
You are looking for the inverse Laplace transform of
g[s_] = (1 - Exp[-Sqrt[1 + s] x])/(1 + s);
Looking at the simpler problem
InverseLaplaceTransform[g[s - 1], s, t] // Simplify[#, x > 0] &
1 - Erfc[x/(2*Sqrt[t])]
With x > 0, let
f[t_] = E^-t (1 - Erfc[x/(2*Sqrt[t])]);
g[s] == LaplaceTransform[f[t], t, s] // Simplify[#, x > 0] &
True
So f[t] is the inverse Laplace transform of g[s]
inttrans[invlaplace]( (1- exp(-sqrt(1+s)*x))/(1+s),s,t) assuming positive;
note that Maple can do it directly, just needed assumption on x>0
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