I need to plot a function in implicit form as below:
ContourPlot3D[{73.04 z*y^2 - 293.04 z*x^2 ==
2605.68 y^2 - 2605.68 x^2}, {x, 0, 3}, {y, 0, 6}, {z, 0, 15}]
but with the constraint x > y. How can I do this with Mathematica?
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1 Answer
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Take a look at RegionFunction, e.g.:
ContourPlot3D[{73.04 z*y^2 - 293.04 z*x^2 == 2605.68 y^2 - 2605.68 x^2},
{x, 0, 10}, {y, 0, 20}, {z, 0, 15},
RegionFunction -> Function[{x, y, z, f}, x > y]]
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$\begingroup$ thank you very much! this also works! $\endgroup$ Jun 14, 2014 at 7:26
ContourPlot3D[{73.04 z*y^2 - 293.04 z*x^2 == 2605.68 y^2 - 2605.68 x^2}, {x, 0, 3}, {y, 0, 6}, {z, 0, 15}, RegionFunction -> Function[{x, y, z}, x > y]]? $\endgroup$RegionFunction? (I've not tested this). That is, for CP3D, MM supplies 4 arguments to the function (I was surprised it "matched" a function with only 3 as in your comment), so I'm guessing it wraps theRegionFunctionspecified in a way that some arguments become optional. Thoughts? $\endgroup$RegionFunctionitself, it explicitly shows four for CP3D et al. $\endgroup$