I would like make the attached image by Mathematica.
someone who could help me?
Thank!
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3$\begingroup$ Or CompleteKaryTree $\endgroup$– ÖskåJun 12, 2014 at 14:20
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$\begingroup$ And at least but not last.., have you even tried anything? Like getting the coordinates of the points? $\endgroup$– ÖskåJun 12, 2014 at 15:05
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$\begingroup$ Now I just saw the comments ... thanks everyone for the help $\endgroup$– user15850Jun 13, 2014 at 6:46
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2 Answers
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Not a perfect match but a start
Partition[Table[Column[{"i = " <> ToString[2^(n - 1)],
CompleteKaryTree[n,
ImagePadding ->
10, (AbsoluteOptions[
CompleteKaryTree[n, VertexLabels -> "Name", ImagePadding -> 10],
VertexCoordinates] /. {x_?NumericQ, y_?NumericQ} :> {x, -y})],
"\[Omega] = " <> ToString[n]}, Center], {n, 2, 5}], 2] // Grid
answered Jun 12, 2014 at 16:09
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If you have Version 9, you can use the GraphLayout suboptions as follows:
bbt[n_] :=
Labeled[GraphUnion[CompleteKaryTree[n], Graph[{UndirectedEdge[0, 1]}],
BaseStyle ->Directive[Opacity[1], Black, PointSize[.015]],
EdgeStyle -> Directive[{Black, Thick}], AspectRatio -> 1,
VertexShapeFunction -> "Point", ImageSize -> 300,
GraphLayout -> {"LayeredEmbedding", "RootVertex" -> 0,
"Orientation" -> Bottom,
LayerSizeFunction -> (If[# == 1, 1, 2^(n - #)] &)}],
{"i = " <> ToString[2^(n - 1)],"\[Omega] = " <> ToString[n]},
{Top, Bottom}];
Row[bbt /@ Range[2,7], Spacer[5]]
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$\begingroup$ I'm afraid that it doesn't look the same on v8. None of the
GraphLayoutoptions seem to work for me. $\endgroup$– ÖskåJun 13, 2014 at 9:26 -
$\begingroup$ @Öskå, right - these
GraphLayoutoptions are new-in-version-9. $\endgroup$– kglrJun 13, 2014 at 9:31 -
$\begingroup$ Well, they seem to be very useful! You already have my +1 $\endgroup$– ÖskåJun 13, 2014 at 9:38
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$\begingroup$ Well, your output looks like what the OP desired, the raw one from
CompleteKaryTreeis getting flatter and flatter. $\endgroup$– ÖskåJun 13, 2014 at 9:52