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I've a list of lists,

tl = {{True, False, m12}, {False, m22, m33}, {m32, False, True}}

and each nested list has the same length, What is the proper way to replace the occurances of all m* values, i.e., m12, m22, etc., with a particular value say x.

All I want is this result

tl = {{True, False, x}, {False, x, x}, {x, False, True}}`

Any help will be appreciated.

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  • $\begingroup$ Is there anything other than True, False and m*? $\endgroup$
    – Kuba
    Jun 7, 2014 at 19:23
  • $\begingroup$ No there are only True, False or m* $\endgroup$
    – aark
    Jun 7, 2014 at 19:30

3 Answers 3

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One rather literal (string-based) interpretation of your question:

tl = {{True, False, m12}, {False, m22, m33}, {m32, False, True}};

tl /. s_ /; StringTake[ToString[s], 1] == "m" :> X

{{True, False, X}, {False, X, X}, {X, False, True}}

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tl = {{True, False, m12}, {False, m22, m33}, {m32, False, True}};

Replace[tl, Except[True | False] :> z, {2}]

(* {{True, False, z}, {False, z, z}, {z, False, True}} *)
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In this way the True and False conditions are analyzed

tl = {{True, False, m12}, {False, m22, m33}, {m32, False, True}}; 
Map[If[ToString[#1] == "True" || ToString[#1] == "False", #1, 
   x] & , tl, {2}]

$\left( \begin{array}{ccc} \text{True} & \text{False} & x \\ \text{False} & x & x \\ x & \text{False} & \text{True} \\ \end{array} \right)$

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