I want to plot multiple functions with the same settings side-by-side, so I use the pure function construct (for clarity, I only use one function in this example)

   {x, 0, 1}
   ] & /@
   Chop[x, 0.5]

however, it somehow ignores the Chop function:

enter image description here

If I plot the function directly

   Chop[x, 0.5],
   {x, 0, 1}

everything works as expected:

enter image description here

I get similar behaviour with Plot3D. Do you see a problem in my code? Does the pure function and Map mechanism (/@) have something to do with it?

PS: I, in fact, want to use Plot3D. That's why I want to draw multiple plots next to each other instead of plotting all functions within one graphics object. I only chose showing the problem using Plot function in order to make the example simpler.

  • 2
    $\begingroup$ Check the output of Chop[x, 0.5]... now you can see that the solution is to prevent Chop[...] inside the {...} from being evaluated until it is "inside" Plot. Now try with Unevaluated@Chop[x, 0.5]. $\endgroup$
    – rm -rf
    May 21, 2014 at 13:45

1 Answer 1


Chop[x, 0.5] evaluates to x because x is symbolic and not a number. Hence your map is equivalent to

Plot[...] & /@ {x}

which is what you see. The solution then is to prevent Chop from evaluating until it is "inside" Plot and this can be done with Unevaluated:

Plot[#, {x, 0, 1}] & /@ {Unevaluated@Chop[x, 0.5]}

  • $\begingroup$ Thank you very much for your valuable explanation! Now it works like a charm. $\endgroup$
    – ivokabel
    May 21, 2014 at 14:28

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