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I have been using ArrayPlot to show off some information. Currently, my datasets are like so:

data1={2, 6, 3, 4, 8, 5, 13, 11, 33, 21, 29, 21, 42, 29, 36};
data2={0, 1, 9, 1, 3, 0, 5, 3, 20, 16, 4, 13, 7, 10, 7};
data3={10, 3, 2, 0, 2, 1, 0, 0, 14, 2, 1, 12, 6, 0, 10};
data4={0, 0, 0, 2, 0, 1, 4, 0, 0, 4, 0, 4, 1, 3, 2};
data5={0, 3, 0, 3, 0, 0, 0, 3, 3, 2, 1, 14, 4, 2, 4};

etc.

The plot command

ArrayPlot[{globeCHR, starCHR, telegramCHR, gazetteCHR, citizenCHR}, 
 FrameTicks -> All] 

reveals the following:

enter image description here

So far so good - it vividly shows what I am trying to visualize.

The problem comes with the following. I would like to give my datasets along the y axis names: i.e. instead of "1" it might say "Cats" and instead of "2" it might say "Dogs." Similarly, the bottom axis needs to go from 1997 to 2010 (years).

I have generated a list of the years as such yearlist = Range[1997, 2011, 1], which lines up in length to the datasets. Matched pairs of data created by Transpose@ the two lists hasn't worked either..

Would there be a way to have the x axis demonstrate the text of the datasets, and the y axis show the data progressing from the year 1997 to 2010? Thank you very much.

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The FrameTicks should be entered in the following format:

FrameTicks->{
    {{ytick1, yvalue1}, {ytick2, yvalue2},...}, 
    {{xtick1, xvalue1}, {xtick2, xvalue2},...}
}

So here's an example for your case that shows how to label the ticks:

xticks = Transpose[{Range@15, Range[1997, 2011]}];
yticks = Transpose[{Range@5, {"Cats", "Dogs", "Sheep", "Frogs", "Mice"}}];
ArrayPlot[RandomReal[1, {5, 15}], FrameTicks -> {yticks, xticks}]

enter image description here

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  • $\begingroup$ This fails for me if you are doing a 2x2 array, as in ArrayPlot[RandomReal[1, {#1, #2}], FrameTicks -> {yticks[[;; #1]], xticks[[;; #2]]}] &[2, 2]. It works in other cases. As a workaround for the 2x2 case, just add on a junk value for xticks or yticks, it will just ignore the extra. For example, this works ArrayPlot[RandomReal[1, {#1, #2}], FrameTicks -> {yticks, xticks[[;; #2]]}] &[2, 2]. There is probably a better way of doing in though. (yticks and xticks are as defined in your answer). $\endgroup$ – Brian Moths Feb 17 '17 at 16:29

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