3
$\begingroup$

I wonder if there is an easy way to convert from TableForm to Grid. I have an existing data format that uses the Table function that I’d like to prettify….

Let’s setup a nested table as follows: 

params = {"A", "B", "C", "D"};  (*example, can be more *);
axes = {"x", "y", "z”}; (*fixed number*) ;
mean = {l1, l2, l3, l4, l5, l6, l7, l8, l9, l10, l11, l12}; (*example data, maybe more*);
stdev = {m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12};
stat = {n1, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, n12};
labels = {"params", "axes", "mean\[PlusMinus]stdev", "other stat"};

My data format is as follows: 

expr = MapThread[{#1, {#2, #3}, #4} &, {Flatten@
 Table[axes, {i, 1, Length@params}], mean, stdev, stat}];
mytable = MapThread[{#1, #2} & , {params, Partition[expr, 3]}];

Visualizing the table: 

TableForm[mytable]

TableForm output

I’ve been banging my head on how to format this table using Grid while maintaining the general structure of the table.

Q1. What is the best way to convert this from TableForm to a Grid.

Q2. Is there a better data structure I could use that would allow me to use TableForm or Grid interchangeably?

Related Question:

Grid - sizing and spacing problems with spanning cells

Improve this question
$\endgroup$
3
  • $\begingroup$ So your question is how to get the same result with Grid? Are Columns/Rows allowed? $\endgroup$ – Kuba♦ Mar 3 '14 at 22:04
  • $\begingroup$ rows alignment - related topic $\endgroup$ – Kuba♦ Mar 3 '14 at 22:09
  • $\begingroup$ @Kuba: yes. I’d like to figure out how to get similar result with Grid. Sure use Columns/Rows inside the grid if you’d like… $\endgroup$ – Pam Mar 3 '14 at 22:21
2
$\begingroup$

This is not the shortest one but I like to use it when I'm making complicated grid layouts.

Basically it is about creating empty grid and fill it with the content you want step by step.

m = ConstantArray["", {12, 4}];
m[[2 ;; ;; 3, 1]] = params; 
m[[;; , 2]] = Join @@ ConstantArray[axes, 4];
m[[;; , 3]] = Column /@ Transpose[{mean, stdev}];
m[[;; , 4]] = stat;
m = Join[{labels}, m];


Grid[m, Dividers -> {Thread[{1, 2, -1} -> 1], Thread[{1, 2, -1} -> 1]},
        ItemStyle -> {{Directive[Bold, 18]}, {Directive[Bold, 18]}}]

enter image description here

Improve this answer
$\endgroup$
3
  • $\begingroup$ thanks. This is a good starting point. Any hints on best practice for formatting the above grid? Say drawing grid lines, applying formatting to labels and aligning various columns and numbers? $\endgroup$ – Pam Mar 3 '14 at 23:36
  • $\begingroup$ @Pam I've made an edit. Also take a look at related $\endgroup$ – Kuba♦ Mar 4 '14 at 0:03
  • $\begingroup$ Thanks for the help. I appreciate it. I have a couple more questions. Specifically dealing with very long text and formatting column sizes. For instance, if I change params to params = {"Some Very Very Very Long Text", "B", "C", "D”}; and have to size the columns by adding ItemSize -> {{18, 5, 10, 5}, {}} it seems to produce some strange behavior in the columns. Specifically the spacing between x,y and z changes… how do I get around this? $\endgroup$ – Pam Mar 4 '14 at 15:47
2
$\begingroup$

The following method is not fast, but very flexible if you have complicated nested Grid :

mytable //
   ReplacePart[#, x : {_, _, _, 2} :> Column[ Extract[#, x], Dividers -> None]] & //
   ReplacePart[#, x : {_, 2} :> Grid[ Extract[#, x], Dividers -> None]] & // 
 Grid [#, Dividers -> None, ItemSize -> {{0, 7}, 7}] &

enter image description here

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.