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I have some familiarity with Mathematica, but have no experience with any Boolean computation. Suppose we have the Boolean formula $(x_1 \lor x_2) \land (x_2 \lor x_3)$. This can be simplified by applying rules of Boolean logic, as follows.

$$\begin{align} &(x_1 \lor x_2) \land (x_2 \lor x_3) \\ &= (x_1 \land x_2) \lor (x_1 \land x_3) \lor (x_2 \land x_2) \lor (x_2 \land x_3) \\ &=x_2 \lor (x_1 \land x_2) \lor (x_2 \land x_3) \lor (x_1 \land x_3) \\ &=x_2 \lor (x_1 \land x_3) \end{align}$$

Can formulas of Boolean variables be computed in Mathematica 9? Can Mathematica apply rules of Boolean logic to make simplifications like as shown above?

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Yes.

For your example, e.g., BooleanMinimize[(x1 || x2) && (x2 || x3)] outputs (x1 && x3) || x2

FullSimplify will also do basic simplifications on boolean constructs, but the boolean specific functions available in MM give you more options & flexibility.

You can enter the traditional characters is desired using MM character names, and get the output using traditional characters also, e.g. BooleanMinimize[(x1 || x2) && (x2 || x3)]//TraditionalForm

There's a nice article in the Mathematica Journal.

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  • $\begingroup$ You should review too LogicalExpand because it's very useful if you handled with logical expression. e.g In the particular example above, the outcome is the same by BooleanMinimize. $\endgroup$
    – Jonathan Prieto-Cubides
    Feb 3, 2014 at 7:04
  • $\begingroup$ It works. BTW, is there a way to get Mathematica to output the result in symbols $\land$ instead of &&, and $\lor$ instead of ||? $\endgroup$
    – T. Webster
    Feb 3, 2014 at 7:52
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    $\begingroup$ @Identity: Just add //TraditionalForm to end, or enclose whatever you do in TraditionalForm[...] - I'll edit answer. $\endgroup$
    – ciao
    Feb 3, 2014 at 8:13

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