# Plotting a curve in 3D [duplicate]

This question already has an answer here:

Say I have two polynomials in $\mathbb{R}[X,Y,Z]$, whose intersection of zero loci correspond to a curve in the 3D space.

What is the best way to plot the curve?

## Example:

$$f = X^2+Y^2-Z^2, \qquad g = 2X^3+Y^3-Z$$ I want to plot the curve given by $$\begin{cases} &X^2+Y^2=Z^2 \\\\ &2X^3+Y^3=Z \end{cases}$$

## marked as duplicate by Kuba♦, Ajasja, Sjoerd C. de Vries, Rahul, Mr.Wizard♦Jan 17 '14 at 12:41

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

## 1 Answer

Directly from Highlight the Intersection of Two Surfaces

Is this what you are looking for?

h = x^2 + y^2 - z^2;
g = 2 x^3 + y^3 - z;
ContourPlot3D[{h == 0, g == 0}, {x, -2, 2}, {y, -2, 2}, {z, -2, 2},
MeshFunctions -> {Function[{x, y, z, f}, h - g]},
MeshStyle -> {{Thick, Blue}}, Mesh -> {{0}}, ContourStyle -> Directive[Orange,
Opacity[0.5], Specularity[White, 30]]] • Nice. How to do the same but with intersections of parallel planes with coordinate planes. – Sigur Mar 25 '14 at 23:21