0
$\begingroup$

If I have a fractional value, how can I truncate (not round) that to a certain number of bits, like 8?

For example, for Pi 3.141569265359... the fractional part is 0.141569265359...

NumberForm[BaseForm[FractionalPart[N[Pi]],2],8]

0.00100100001111110110101010001

But this is giving me 8 decimal digits of PI in base 2. What I want is 8 binary digits in base 2.

$\endgroup$
1
$\begingroup$

NumberForm is for representation purposes only. I suggest you use RealDigits, and then take the number of bits you need from its first returned element or, better yet

Rest[ First[ RealDigits[FractionalPart[N[Pi]], 2, 8+1]]]

EDIT: corrected to give only the bits needed.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.