Update
Solve[N[Table[BernoulliB[n, z], {n, 10, 10}] == 0]]
{{z -> -0.5841145496910024` - 0.435309007896589` I}, <<4>>}
I am then finding and replacing z ->
with blank to get :
{{-0.5841145496910024` - 0.435309007896589` I}, <<4>>}
I am then finding and replacing ` I}
with }
to get :
{{-0.5841145496910024`-0.435309007896589}, <<4>>}
I am then finding and replacing '
with ,
to get :
{{-0.5841145496910024, -0.435309007896589}, <<4>>}
My question is, is there a way of doing this without all of the find & replace business?
Old
I am generating a list from :
Solve[N[Table[BernoulliB[n, z], {n, 100, 100}] == 0]]
And then manually finding and replacing elements in the generated list such as z ->
with Blank
, then finding and replacing , I}
with }
, and so on. I am then producing a list plot form the resultant array. Is there a way of automating this process and producing a list plot directly?
I}
with}
,"? $\endgroup$({Re@z, Im@z} /. sol) // ListPlot
? $\endgroup$Table
here? Why not justSolve[N@BernoulliB[10, z] == 0, z]
? $\endgroup$