As the title says, I want to find a way to increase the size of the dot produced by OverDot[]. Here is a simple code

f = (x^2*px^2 - px^2*(px^2 - 1)) + (x^2 + px^2)/2 - 2*x^4;
cnt = {0.002, 0.015, 0.0312, 0.05, 0.15, 0.3, 0.45, 0.5612, 0.64, 0.73, 0.778};
xmin = 1.5;
C0 = ContourPlot[f, {x, -xmin, xmin}, {px, -xmin, xmin}, 
Contours -> cnt, ContourStyle -> {Black}, ContourShading -> False, 
FrameLabel -> {"x", OverDot["x"]}, RotateLabel -> False, 
Axes -> False, FrameStyle -> Directive[FontSize -> 22, FontFamily -> "Helvetica"], 
PlotRange -> xmin, ImageSize -> 550]

which gives this output


We see, that even if I used a relative large fonts size (22), the dot above $x$ (OverDot["x"]) at the vertical axes is tiny and hardly visible if I print out this plot. So, my question: is there a way to increase the size of that dot?

Many thanks in advance.


Following @Hector suggestions I used Overscript["x", Style["\[FilledSmallCircle]", FontSize -> 12]] which gives



2 Answers 2


Is this dot large enough for you?

Overscript["x", Style[".", FontSize -> 200]]

Try Esc bu Esc to put a bullet into the upper place holder.

  • $\begingroup$ you may want to specify the FontFamily, as some fonts have a "square" dot, e.g. Style[".", FontFamily -> "Courier", FontSize -> 50] vs Style[".", FontFamily -> "Arial", FontSize -> 50] $\endgroup$ Oct 16, 2013 at 7:01
  • $\begingroup$ Yes, large enough but I want a circle not a square! $\endgroup$
    – Vaggelis_Z
    Oct 16, 2013 at 7:06
  • $\begingroup$ @PinguinDirk I want a circle not a square dot. $\endgroup$
    – Vaggelis_Z
    Oct 16, 2013 at 7:07
  • $\begingroup$ so try Courier, as per my comment $\endgroup$ Oct 16, 2013 at 7:08

I'd do it a bit different. One of the problems is that DiacriticalPositioning is an option for OverscriptBox but causes a meltdown when used with Overscript (and OverDot).

myOverDot /: MakeBoxes[myOverDot[x_], StandardForm] := 
 OverscriptBox["x", "\[FilledSmallCircle]", 
  DiacriticalPositioning -> True]

enter image description here


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