Consider the following line of code:
D[x == y^3 + x y, x, NonConstants -> y]
The output would be:
1 == y + x D[y, x, NonConstants -> {y}] + 3 y^2 D[y, x, NonConstants -> {y}]
This is a confusing and cumbersome notation for the more natural:
1 == y + x y' + 3y^2 y'
I am trying to use the Notation package to help me replace the messy, default, output with the more natural one.
I have not succeeded.
Of-course I have read this Q.
The answer, if relevant, seems inaccessible to me, unfortunately.
Any help would be appreciated.
expr /. D[y, x, NonConstants -> {y}] :> y'[x]
yields1 == y + x y'[x] + 3 y^2 y'[x]
. $\endgroup$ – Artes Oct 11 '13 at 21:55{ l1==r1, l2==r2,..., ln==rn} /. D[y, x, NonConstants -> {y}] :> y'[x]
. $\endgroup$ – Artes Oct 11 '13 at 22:29