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Functions such as GraphDistanceMatrix[] or AdjacencyMatrix[] are available without invoking

Needs["GraphUtilities`"]

.

Why isn't the whole package available when Mathematica starts? Are the functions different after having loaded GraphUtilities?

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  • $\begingroup$ Those are simply different functions with the same name. The package was available in older versions, the built-in functions are new in 8. $\endgroup$
    – Szabolcs
    Mar 21, 2012 at 10:10

1 Answer 1

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If you look at their Contexts, you'll see that all of them are in the System` context and not the GraphUtilities` context.

Context /@ {GraphDistanceMatrix, CharacteristicPolynomial, AdjacencyMatrix}
Out[1]= {"System`", "System`", "System`"}

Some packages are preloaded when the kernel starts — System` is one of them, whereas GraphUtilities` is not. You can see all packages that are pre-loaded with $Packages

$Packages
Out[2]= {"ResourceLocator`", "DocumentationSearch`", "GetFEKernelInit`",
    "JLink`", "PacletManager`", "WebServices`", "System`", "Global`"}
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  • $\begingroup$ @CHM: Which functions are you concerned about. For CharacteristicPolynomial, for example, it $must$ be the System``` context because evaluating ?GraphUtilities``*` does not show any function of the same name in that context. $\endgroup$
    – murray
    Mar 21, 2012 at 20:02
  • $\begingroup$ @murray I've noticed that CharacteristicPolynomial[] is not in GraphUtilities. Edited, thanks. I'm concerned not with a particular example, but with the fact that some functions might have two different definitions when loading a package. $\endgroup$
    – CHM
    Mar 21, 2012 at 20:08
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    $\begingroup$ @CHM: Yes, multiple definitions can be a problem. This seems to happen mostly with add-on packages that are still shipped with Mathematica but whose functions have not yet been moved into the kernel. Of course if you load a package and get shadowing messages, that's a sure tip-off. And you can always qualify the name of a function provided in a package by including the package's context when calling it. $\endgroup$
    – murray
    Mar 22, 2012 at 0:17

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