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I have sphere $(x-1)^2 + (y-2)^2 + (z-3)^2 = 81$. To select two points $A$, $B$ on sphere so that coordinates of $A$, $B$ are six different integer numbers and $AB = 18$, $xyz \neq 0$ I tried.

ClearAll[a, b, r, c];
a = 1;
b = 2;
c = 3;
r = 9; ss = Subsets[{x, y, z} /.
   Solve[{(x \[Minus] a)^2 + (y \[Minus] b)^2 + (z \[Minus] c)^2 == 
      r^2, x y z != 0}, {x, y, z}, Integers], {2}];
t = Select[ss, And @@ Unequal @@@ Subsets[Flatten[#], {2}] &];
Select[t, Apply[EuclideanDistance, #] == 18 &]

My question: besides $AB = 18$, are there any other integers of $AB$?

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2
  • $\begingroup$ Solve[{(x [Minus] 2)^2 + (y [Minus] 4)^2 + (z [Minus] 6)^2 == 81}, {x, y, z}, PositiveIntegers] $\endgroup$ Commented Aug 9 at 6:33
  • $\begingroup$ @Ghoster Thank you very much. $\endgroup$ Commented Aug 10 at 2:43

3 Answers 3

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Yes. You can find many other integral points using FindInstance[]:

ClearAll[x,y,z];
intpoints={x,y,z}/.FindInstance[(x-1)^2+(y-2)^2+(z-3)^2==81,
                      {x,y,z},Integers,999999];
Short[intpoints]

(* {{-8,2,3},{-7,-2,2},{-7,-2,4},{-7,1,-1},{-7,1,7},{-7,3,-1},{-7,3,7},
    {-7,6,2},{-7,6,4},{-6,-2,-1},{-6,-2,7},{-6,6,-1},{-6,6,7},{-5,-4,0},
    {-5,-4,6},{-5,-1,-3},{-5,-1,9},<<68>>,{7,5,-3},{7,5,9},{7,8,0},
    {7,8,6},{8,-2,-1},{8,-2,7},{8,6,-1},{8,6,7},{9,-2,2},{9,-2,4},{9,1,-1},
    {9,1,7},{9,3,-1},{9,3,7},{9,6,2},{9,6,4},{10,2,3}} *)

Then it is easy to see there are other integers of 𝐴𝐵:

Union[EuclideanDistance @@@ Tuples[intpoints, {2}]]

ans

Select[%, IntegerQ]

(* {0, 2, 6, 8, 12, 14, 16, 18} *)

To select AB=18 pairs,

ans = Select[Tuples[intpoints, {2}], (EuclideanDistance @@ #) == 18 &];
Short[ans]

(* {{{-8,2,3},{10,2,3}},{{-7,-2,2},{9,6,4}},{{-7,-2,4},{9,6,2}},{{-7,1,-1},{9,3,7}},{{-7,1,7},{9,3,-1}},{{-7,3,-1},{9,1,7}},{{-7,3,7},{9,1,-1}},{{-7,6,2},{9,-2,4}},<<86>>,{{9,-2,4},{-7,6,2}},{{9,1,-1},{-7,3,7}},{{9,1,7},{-7,3,-1}},{{9,3,-1},{-7,1,7}},{{9,3,7},{-7,1,-1}},{{9,6,2},{-7,-2,4}},{{9,6,4},{-7,-2,2}},{{10,2,3},{-8,2,3}}}*)
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5
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First, find all 102 points on the surface of the sphere that have only integer coordinates, then select end-points of the 40 lines with length 18 and no duplicated coordinates.

\[ScriptCapitalR] = Sphere[{1, 2, 3}, 9];
pts = {x, y, z} /. Solve[RegionMember[\[ScriptCapitalR], {x, y, z}] /. 
  Reals -> Integers, {x, y, z}];
lines = Pick[##, Unequal @@@ Flatten/@##] &@
  Cases[Subsets[pts,{2}], pp_ /;
    Apply[EuclideanDistance, pp] == 18]

Find other values of AB that have solutions:

Pick[Range[18],
  Table[
    Length[Pick[##, Unequal @@@ Flatten /@ ##] &@
      Cases[Subsets[pts, {2}],
        pp_/; Apply[EuclideanDistance, pp] == d]] > 0,
  {d, Range[18]}]]    
(* {6, 12, 18} *)
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  • $\begingroup$ My question: besides AB=18 , are there any other integers of AB ? $\endgroup$ Commented Aug 9 at 7:18
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Find all integer-valued points on the sphere excluding $x y z \ne 0$, then choose pairs with no duplicate values and distance of 18:

SolveValues[
    Element[{x, y, z}, Sphere[{1, 2, 3}, 9]] && x y z != 0,
     {x, y, z}, Integers] //
   Subsets[#, {2}] & // Select[Unequal @@ Flatten@# &] //
 Select[EuclideanDistance @@ # == 18 &]

(* ... *)

Measure distances of point pairs with unique coordinate values and find those which are integer-valued, deduplicating and sorting the result:

SolveValues[
       Element[{x, y, z}, Sphere[{1, 2, 3}, 9]] && x y z != 0,
        {x, y, z}, Integers] //
      Subsets[#, {2}] & // Select[Unequal @@ Flatten@# &] //
    MapApply@EuclideanDistance // Select@IntegerQ // 
  DeleteDuplicates // Sort

 (*  {6, 12, 18} *)
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