I am trying to plot the following graph for different values of t (t=1 to t=10) in one plot.

Plot[Sqrt[a[x/x0[t], t]], {x, 0, x0[t]}, 
 PlotRange -> {{0, 14}, {0, 6}}]

When I use

 Plot[Sqrt[a[x/x0[1], 1]], {x, 0, x0[1]}, 
     PlotRange -> {{0, 14}, {0, 6}}]

I get a correct output. However, when I use this in a for loop (as follows) I get no output.

For[t = 1, t < 10, t++, 
 Plot[Sqrt[a[x/x0[t], t]], {x, 0, x0[t]}, 
  PlotRange -> {{0, 14}, {0, 6}}]]
  • $\begingroup$ Maybe wrap a Print around your Plot[...] Or try a[u_,v_]:=u^3;x0[t_]:=t^4; Table[ Plot[Sqrt[a[x/x0[t], t]],{x,0,x0[t]},PlotRange->{{0,14},{0,6}}],{t,1,10}] but we are just guessing what your a[u_,v_] and your x0[t] are $\endgroup$
    – Bill
    Commented Jul 10 at 15:47
  • $\begingroup$ Thanks. These both work but show many graphs at output. Is there any way one could show them all in one graph with different colors for different values of t? @Bill $\endgroup$ Commented Jul 10 at 16:05

1 Answer 1


You can generate the plots using Table and combine them into one plot with Show.

You don't define the functions a and x0 in your question, so I use dummy definitions as an example:

a[y_, t_] := 2 y^2 + 2 t;
x0[t_] := t + 4;

plot = Show[
    Plot[Sqrt[a[x/x0[t], t]], {x, 0, x0[t]}, 
       PlotRange -> {{0, 14}, {0, 6}}, PlotStyle -> ColorData[97][t]], 

This gives

enter image description here

If you want to a legend showing the color of each t value, first create the legend:

legend = LineLegend @@ Transpose[Table[{ColorData[97][t], t}, {t, 10}]]

then combine it with the plot

Legended[plot, legend]
  • $\begingroup$ Is it possible to show what t value each color is related to? $\endgroup$ Commented Jul 10 at 16:46
  • $\begingroup$ yes, see my edit for how to add a legend $\endgroup$
    – tad
    Commented Jul 10 at 16:53
  • $\begingroup$ would it be possible to add the legend label "t" to the legend too? $\endgroup$ Commented Jul 10 at 17:05
  • $\begingroup$ yes. Check the documentation of LineLegend for ways to format the legend. The option LegendLabel adds a label. $\endgroup$
    – tad
    Commented Jul 10 at 18:07

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