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I am trying to code a particular Fox-H function in Mathematica, $H_{2,2}^{2,0}\left(z\left| \begin{array}{c}(1,1),(1,\alpha)\\(1,1),(1,2)\\\end{array} \right.\right)$. I've been trying to use the format provided by the FoxH Wolfram Documentation page.

The best I have been able to do is get $H_{2,2}^{0,0}\left(z\left| \begin{array}{c}(1,1),(1,\alpha)\\(1,1),(1,2)\\\end{array} \right.\right)$ using the Mathematica code:

FoxH[{{}, {{1, 1}, {1, \[Alpha]}}}, {{}, {{1, 2}, {1, 1}}}, z] // TraditionalForm

The TraditionalForm command allows you to see how Mathematica is reading your input, so this is a good check. Note that this function only differs in that I need m = 2, and get it only to m = 0 (see Mathematica Fox-H webpage for details).

Any help would be appreciated. Thanks

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  • $\begingroup$ Should n not be 2 instead of 0 for your case? Then H reads: H[{{{1, 1}, {1, \[Alpha]}}, {{1, 1}, {1, 2}}}, z] $\endgroup$ Commented Feb 18 at 10:11

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FoxH[{{}, {{a, b}, {c, d}}}, {{{e, f}, {g, h}}, {}}, 
  z] // TraditionalForm

enter image description here

By the way, TeXForm fails on FoxH on version 13.0.1

TeXForm[FoxH[{{}, {{a, b}, {c, d}}}, {{{e, f}, {g, h}}, {}}, z]]
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  • $\begingroup$ TeXForm fails on FoxH on version 14.0.0 to. It's a Bug. $\endgroup$ Commented Feb 18 at 11:47
  • $\begingroup$ Thanks, azerbajdzan, it worked. Also appreciate you raising the TeXForm issue and Mariusz providing the reason why it's not working. Cheers! $\endgroup$ Commented Feb 19 at 3:44

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