# Simplifying expressions with square roots

I would like Mathematica to simplify this expression:

$4 \left(16 \sqrt{\left(-1+2 c^2\right)^2}-32 c^2 \sqrt{\left(-1+2 c^2\right)^2}+\sqrt{\left(1-8 c^2+8 c^4\right)^2}\right)^2$

expression = 4*( 16*Sqrt[(-1 + 2*c^2)^2] - 32*c^2*Sqrt[(-1 + 2*c^2)^2]
+ Sqrt[(1 - 8*c^2 + 8*c^4)^2])^2;


I have tried

PowerExpand[expression]

FullSimplify[expression]


but they did not simplify expression.

• are you assuming that c is Real and did you tell Mathematica that? – bobthechemist Jul 28 '13 at 2:07

The simplification that I think you are looking for only works if you tell Mathematica to assume c is real. Try

Simplify[4*(16*Sqrt[(-1 + 2*c^2)^2] -
32*c^2*Sqrt[(-1 + 2*c^2)^2] +
Sqrt[(1 - 8*c^2 + 8*c^4)^2])^2,
c ∈ Reals]


4 ((16 - 32 c^2) Abs[1 - 2 c^2] + Abs[1 - 8 c^2 + 8 c^4])^2

We should exploit the second argument in Simplify or FullSimplify being an assumption on possible variables or symbols in a given axpression. For more complete discussion of simplification methods see the answers to this question What is the difference between a few simplification techniques?.

One should have consider a few cases since we could use various assumptions. Let's start with plotting graphs of polynomial functions apprearing in the expression. We'd like to distinguish cases where 1 - 8 c^2 + 8 c^4 and 1 - 2 c^2 are non-negative.

Plot[{ 1 - 8 c^2 + 8 c^4, 1 - 2 c^2}, {c, -4/3, 4/3},
PlotLegends -> "Expressions", PlotStyle -> Thick] There are two independent terms which can be simplified in different ways with respect to assumptions given, e.g.

Simplify[ Sqrt[(-1 + 2 c^2)^2], #]& /@ {-(1/Sqrt) < c < 1/Sqrt, 1/Sqrt < c} //
Column

 1 - 2 c^2
-1 + 2 c^2


We shouldn't impose accidental assumptions since expressions couldn't be simplified to the simplest form (appropriate assumptions for the first term, in general will not be adequate for the other one), e.g.

Simplify[ expression, #] & /@ {-(1/Sqrt) < c < 1/Sqrt, 1/Sqrt < c} // Column

4 ( 16 (1 - 2 c^2)^2 + Abs[1 - 8 c^2 + 8 c^4])^2
4 (-16 (1 - 2 c^2)^2 + Abs[1 - 8 c^2 + 8 c^4])^2


Here Sqrt[(1 - 8 c^2 + 8 c^4)^2] could be simplified only to Abs[1 - 8 c^2 + 8 c^4] since it is the most general (and the simplest) form satisfying imposed assumptions.

Now, in order to complete simplification we need to deal with Reduce for writing down different assumptions:

Grid[(cs = Table[ Reduce[ g[1 - 8 c^2 + 8 c^4, 0] && h[1 - 2 c^2, 0], c],
{g, {GreaterEqual, Less}}, {h, {GreaterEqual, Less}}]),
Frame -> All] // TraditionalForm and the simplifications are respectively:

Grid[ Map[ Simplify[ 4(16Sqrt[(-1 + 2c^2)^2] - 32c^2 Sqrt[(-1 + 2 c^2)^2] +
Sqrt[(1 - 8c^2 + 8c^4)^2])^2, #] &, cs, {2}],
Frame -> All] // TraditionalForm In general for more involved expressions one should deal with FullSimplify, nevertheless we get in our case the same expressions with Simplify.

• Very useful stuff. I need you in my corner if I ever return to Project Euler problems. :-) – Mr.Wizard Jul 29 '13 at 14:57