The analytic expression for $h$ is the following function on $l$, $p$, $\gamma$: $$ h=2^{\left| l \right|+2}p!\left( \left| l \right|+p \right) !\gamma ^2\left( \sum_{m=0}^p{\frac{\left( -2 \right) ^m\varGamma \left( m+\left| l \right|/2+1 \right)}{\left( p-m \right) !\left( \left| l \right|+m \right) !m!\left( 1+\gamma ^2 \right) ^{m+\left| l \right|/2+1}}} \right) ^2 $$
h[l_, p_, \[Gamma]_] :=
2^(Abs[l] + 2) p! (Abs[l] +
p)! \[Gamma]^2 (Sum[((-2)^m Gamma[
m + Abs[l]/2 +
1])/((p - m)! (Abs[l] + m)! m! (1 + \[Gamma]^2)^(m +
Abs[l]/2 + 1)), {m, 0, p}])^2;
When $p=0$:
We can find the relationship between $\gamma$ and $l$ for the condition that $h$ is at its maximum value.
$Assumptions = \[Gamma] > 0;
Reduce[D[h[l, 0, \[Gamma]], \[Gamma]] == 0, \[Gamma]] // FullSimplify
[Gamma] == 1/Sqrt[1 + Abs[l]]
i.e. $\gamma =\frac{1}{\sqrt{1+\left| l \right|}}$
But as $p$ increases, the expression for $h$ becomes complicated, and perhaps when $h$ is maximum, it is impossible to find the correspondence between $\gamma$ and $l$. Although I can calculate the result by numerical solution, I ideally can solve the correspondence between $\gamma$ and $l$, for example, when $p=1,2,3...$.
For example: when $l=1$, $p=2$.
Plot[h[1, 2, \[Gamma]], {\[Gamma], 0, 10}, PlotRange -> All]
NMaximize[h[1, 2, \[Gamma]], {\[Gamma], 0, 10}]
{0.162661, {[Gamma] -> 0.311767}}