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I wanted to parameterize and draw a pyramid with a square base. The base was parameterized as a function of t , getting:

Show[ParametricPlot3D[{t, 0, 0}, {t, 0, 4}], 
 ParametricPlot3D[{4, t - 4, 0}, {t, 4, 8}], 
 ParametricPlot3D[{12 - t, 4, 0}, {t, 8, 12}], 
 ParametricPlot3D[{0, 16 - t, 0}, {t, 12, 16}], PlotRange -> Full]

The pyramid would be lifted from a point (2,2,8) , but when I draw the line between that vertex and one of the base lines, nothing works, and it separates all the graphs. Is there a better way for me to do this?

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  • $\begingroup$ Do you really need the parametrization, or do you just want to draw a pyramid? In latter, you can use Pyramid. Also, instead of ParametricPlot3D, you can simply use Line. $\endgroup$
    – Domen
    Mar 26 at 20:51
  • $\begingroup$ I actually need the parametrization. I already used the Line command to do that but it's not really what I wanted. $\endgroup$
    – Sara
    Mar 26 at 20:53

1 Answer 1

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Show[
{ParametricPlot3D[{0, 0, 0} t + (1 - t) {4, 0, 0}, {t, 0, 1}],
  ParametricPlot3D[{4, 0, 0} t + (1 - t) {4, 4, 0}, {t, 0, 1}],
  ParametricPlot3D[{4, 4, 0} t + (1 - t) {0, 4, 0}, {t, 0, 1}],
  ParametricPlot3D[{0, 4, 0} t + (1 - t) {0, 0, 0}, {t, 0, 1}],
  ParametricPlot3D[{0, 0, 0} t + (1 - t) {2, 2, 6}, {t, 0, 1}],
  ParametricPlot3D[{4, 0, 0} t + (1 - t) {2, 2, 6}, {t, 0, 1}],
  ParametricPlot3D[{0, 4, 0} t + (1 - t) {2, 2, 6}, {t, 0, 1}],
  ParametricPlot3D[{4, 4, 0} t + (1 - t) {2, 2, 6}, {t, 0, 1}]
},  PlotRange -> Full]

You forgot the list bracket of objects. The line parametrization is done conventionally by the convex combination of two points with factors t amd 1-t for t in the unit interval

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  • $\begingroup$ Oh, I see. Thank you for the help! $\endgroup$
    – Sara
    Mar 26 at 22:00
  • $\begingroup$ Show works with or without the curly brackets, as illustrated in the documentation. $\endgroup$
    – bbgodfrey
    Mar 27 at 1:47

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