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I have the following expression: $$(\nabla+\vec{P})^2$$ where $P=(r\cos\theta sin\phi,r^4\sin\theta,r\cos^3\phi)$

I would like to open the brackets and simplify the expression.

Are there in Mathematica ways analytically do it?

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  • $\begingroup$ I think the expression should correctly be $(\nabla +P)\cdot( \nabla +P)$ $\endgroup$ Mar 8, 2023 at 17:49

1 Answer 1

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I think the expression should correctly be $(\nabla +P)\cdot( \nabla +P)$

Expression without brackets follows to $ \nabla \cdot \nabla +\nabla \cdot P+P \cdot \nabla + P \cdot P $

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