I'm very concerned. As far as I know, the output should be:
$x < 0\ ||\ x> 0$
$y < 0\ ||\ y> 0$
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1 Answer
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Observe that
g[x]
returns
x
So, when you write
FunctionDomain[g[x], x, Reals]
it is really writing
FunctionDomain[x, x, Reals]
On way to bypass, is to Hold like so:
FunctionDomain[Hold[x^2/x], x, Reals]
FunctionRange[Hold[x^2/x], x, y, Reals]
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$\begingroup$ I see, thanks a lot! But is there a way to pass a variable or a function that contains the expression and get the correct result? $\endgroup$ Feb 24 at 10:29
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$\begingroup$ @AndreyLeshchev-Romanenko I guess you could do something like:
g[x_] := x^2/x // Holdand thenFunctionDomain[g[x], x, Reals]but I am not sure how satisfactory that is for your purposes $\endgroup$– bmfFeb 24 at 10:35 -
$\begingroup$ yeah, that's exactly what I need for now. Thank you! $\endgroup$ Feb 24 at 10:36
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$\begingroup$ @AndreyLeshchev-Romanenko glad I was able to help :-) $\endgroup$– bmfFeb 24 at 10:37