A great answer by Alex is to be found here for my original question: Numerically solving a system of SDE's with Levy noise?
Now Let us perturb this system with time delays so the system is:
\begin{align} dS&=\big[A-(\mu_1+\kappa) S(t)-\beta S(t) D(t)+ \kappa S(t-\tau_1)e^{-\mu\tau_1}+\gamma I(t-\tau_2)e^{-\mu\tau_2}\big]dt+\sigma_1 S(t) dW_1(t)+\int_U \lambda_1(u)S(t-)\tilde{N}(dt,du)\\[1ex] dI&=\big[\beta S(t) D(t)-(\mu_2+\gamma)I(t)\big]dt+\sigma_2 I(t) dW_2(t)+\int_U \lambda_2(u)I(t-)\tilde{N}(dt,du)\\[1ex] dD&=\big[\eta(I(t)-D(t)]dt+\sigma_4 D(t) dW_4(t)+\int_U \lambda_4(u)D(t-)\tilde{N}(dt,du) \end{align}
where $\kappa$ is a postive and $\tau_1$ and $\tau_2$ are nonnegative with $t\geq -\tau$, where, $\tau=\max\lbrace \tau_1, \tau_2\rbrace$.
Code:
SeedRandom[1234];
A (*Recruitment rate*)= {0.9, 0.3, 0.6, 0.6};
µ1 (*Natural mortality rate of S*)= {0.3, 0.3, 0.4, 0.4};
\[Beta] (*Transmission rate*)= {0.07, 1.3, 0.35, 0.8};
\[Gamma] (*Recovered rate*)= {0.05, 0.05, 0.2, 0.3};
µ2 (*General mortality of I*)= {0.5, 0.5, 0.3, 0.3};
\[Eta] (*Exponentially fading memory rate*)= {0.09, 0.09, 0.7, 0.2};
\[Sigma]1 (*Intensity of W1(t)*)= {0.15, 0.15, 0.2, 0.169};
\[Sigma]2 (*Intensity of W2(t)*)= {0.25, 0.25, 0.15, 0.15};
\[Sigma]4 (*Intensity of W4(t)*)= {0.27, 0.27, 0.13, 0.13};
\[Lambda]1 (*Jump intensity of S*)= {0.2, 0.2, 0.5, 0.5};
\[Lambda]2 (*Jump intensity of I*)= {0.23, 0.23, 0.3, 0.3};
\[Lambda]4 (*Jump intensity of D*)= {0.1, 0.1, 0.7, 0.7};
\[Kappa](*----*)= {0.2, 0.1, 0.7, 0.7};
\[Tau]1(*----*)= {1, 0.1, 0.7, 0.7};
\[Tau]2(*----*)= {1, 0.1, 0.7, 0.7};
tmax = 301; pWe1 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW1 =
Interpolation[Table[{(j - 1), pWe1[[j]]}, {j, Length[pWe1]}],
InterpolationOrder -> 1]; pWe2 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW2 =
Interpolation[Table[{(j - 1), pWe2[[j]]}, {j, Length[pWe2]}],
InterpolationOrder -> 1]; pWe4 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW4 =
Interpolation[Table[{(j - 1), pWe4[[j]]}, {j, Length[pWe4]}],
InterpolationOrder -> 1];
pL1 = RandomFunction[PoissonProcess[1.], {0, tmax}]; pL2 =
RandomFunction[PoissonProcess[1.1], {0, tmax}]; pL4 =
RandomFunction[PoissonProcess[.9], {0, tmax}]; ListStepPlot[{pL1,
pL2, pL4}];
dpL1 = pL1["SliceData", Range[tmax]] // First // Differences; dpL2 =
pL2["SliceData", Range[tmax]] // First // Differences; dpL4 =
pL4["SliceData", Range[tmax]] // First // Differences;
L1[t_] := If[t < 1, 0, dpL1[[Round[t]]]]/tmax;
L2[t_] := If[t < 1, 0, dpL2[[Round[t]]]]/tmax;
L4[t_] := If[t < 1, 0, dpL4[[Round[t]]]]/tmax;
eq1 = -s'[t] + (a - (mu1 + kappa) s[t] - beta s[t] d[t] +
kappa s[t - tau1] Exp[mu tau1] +
gamma i[t - tau2] Exp[mu tau2]) + sigma1 s[t] dW1[t] +
lambda1 s[t] L1[t];
eq2 = -i'[t] + (beta s[t] d[t] - (mu2 + gamma) i[t]) +
sigma2 i[t] dW2[t] + lambda2 i[t] L2[t];
eq3 = -r'[t] + (gamma i[t] - mu3 r[t]);
eq4 = -d'[t] + eta (i[t] - d[t]) + sigma4 d[t] dW4[t] +
lambda4 d[t] L4[t];
ic = {s[0] == 0.6, i[0] == 0.3, d[0] == 0.05};
rul[j_] := {a -> A[[j]], beta -> \[Beta][[j]], gamma -> \[Gamma][[j]],
eta -> \[Eta][[j]], mu1 -> µ1[[j]], mu2 -> µ2[[j]],
sigma1 -> \[Sigma]1[[j]], sigma2 -> \[Sigma]2[[j]],
sigma4 -> \[Sigma]4[[j]], lambda1 -> \[Lambda]1[[j]],
lambda2 -> \[Lambda]2[[j]], lambda4 -> \[Lambda]4[[j]],
kappa -> \[Kappa][[j]], tau1 -> \[Tau]1[[j]], tau2 -> \[Tau]2[[j]]};
eqn[j_] := {eq1, eq2, eq4} /. rul[j];
sol[j_] :=
NDSolve[{eqn[j] == {0, 0, 0}, ic}, {s, i, d}, {t, 0, tmax - 1}];
With[{sol = sol[1]}, {Plot[Evaluate[s[t] /. sol], {t, 0, tmax - 1},
PlotRange -> All, Frame -> True, PlotStyle -> Green,
FrameLabel -> {"Time t (Days)", "S"}],
Plot[Evaluate[i[t] /. sol], {t, 0, tmax - 1}, PlotRange -> All,
Frame -> True, PlotStyle -> Blue,
FrameLabel -> {"Time t (Days)", "I"}],
Plot[Evaluate[d[t] /. sol], {t, 0, tmax - 1}, PlotRange -> All,
Frame -> True, PlotStyle -> Red,
FrameLabel -> {"Time t (Days)", "D"}]}]
How can we numerically solve this?
Edit: This is the code for the second papers equations(see comments to Alex's answer):
A (*Recruitment rate*)= {1, 0.3, 0.6, 0.6};
mu0 (*Natural mortality rate of S*)= {0.09, 0.3, 0.4, 0.4};
\[Beta] (*Transmission rate*)= {0.18, 1.3, 0.35, 0.8};
\[Gamma] (*Recovered rate*)= {0.55, 0.05, 0.2, 0.3};
\[Delta] (*Recovered rate*)= {0.44, 0.05, 0.2, 0.3};
\[Alpha]1 (*General mortality of I*)= {0.4, 0.5, 0.3, 0.3};
\[Alpha]2 (*General mortality of I*)= {0.02, 0.5, 0.3, 0.3};
\[Epsilon] (*Exponentially fading memory rate*)= {0.6, 0.09, 0.7, 0.2};
\[Rho] (*Exponentially fading memory rate*)= {0.2, 0.09, 0.7, 0.2};
\[Sigma]1 (*Intensity of W1(t)*)= {0.2, 0.15, 0.2, 0.169};
\[Sigma]2 (*Intensity of W2(t)*)= {0.85, 0.25, 0.15, 0.15};
\[Sigma]3 (*Intensity of W4(t)*)= {0.5, 0.27, 0.13, 0.13};
\[Lambda]1 (*Jump intensity of S*)= {0., 0.2, 0.5, 0.5};
\[Lambda]2 (*Jump intensity of I*)= {0., 0.23, 0.3, 0.3};
\[Lambda]3 (*Jump intensity of D*)= {0., 0.1, 0.7, 0.7};
\[Tau]1 (*Jump intensity of S*)= {0.5, 0.2, 0.5, 0.5};
\[Tau]2 (*Jump intensity of I*)= {0.5, 0.23, 0.3, 0.3};
\[Tau]3 (*Jump intensity of D*)= {0.5, 0.1, 0.7, 0.7};
tmax = 5001; pWe1 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW1 =
Interpolation[Table[{(j - 1), pWe1[[j]]}, {j, Length[pWe1]}],
InterpolationOrder -> 1]; pWe2 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW2 =
Interpolation[Table[{(j - 1), pWe2[[j]]}, {j, Length[pWe2]}],
InterpolationOrder -> 1];
pWe3 = RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1,
1]]; dW3 =
Interpolation[Table[{(j - 1), pWe3[[j]]}, {j, Length[pWe3]}],
InterpolationOrder -> 1]; pWe4 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW4 =
Interpolation[Table[{(j - 1), pWe4[[j]]}, {j, Length[pWe4]}],
InterpolationOrder -> 1];
pL1 = RandomFunction[PoissonProcess[1.], {0, tmax}];
pL2 = RandomFunction[PoissonProcess[1.1], {0, tmax}];
pL3 = RandomFunction[PoissonProcess[1.1], {0, tmax}];
pL4 = RandomFunction[PoissonProcess[.9], {0, tmax}];
ListStepPlot[{pL1, pL2, pL3, pL4}];
dpL1 = pL1["SliceData", Range[tmax]] // First // Differences;
dpL2 = pL2["SliceData", Range[tmax]] // First // Differences;
dpL3 = pL3["SliceData", Range[tmax]] // First // Differences;
dpL4 = pL4["SliceData", Range[tmax]] // First // Differences;
L1[t_] := If[t < 1, 0, dpL1[[Round[t]]]]/tmax;
L2[t_] := If[t < 1, 0, dpL2[[Round[t]]]]/tmax;
L3[t_] := If[t < 1, 0, dpL3[[Round[t]]]]/tmax;
L4[t_] := If[t < 1, 0, dpL4[[Round[t]]]]/tmax;
eq1 = -s'[t] + (a - (mu + rho) s[t] - beta s[t] i[t] +
rho s[t - tau1] Exp[-mu tau1] +
gamma i[t - tau2] Exp[-mu tau2] +
epsilon q[t - tau3] Exp[-mu tau3]) + sigma1 s[t] dW1[t] +
lambda1 s[t] L1[t];
eq2 = -i'[t] + (beta s[t] i[t] - (mu + alpha1 + delta + gamma) i[t]) +
sigma2 i[t] dW2[t] + lambda2 i[t] L2[t];
eq3 = -q'[t] + (delta i[t] - (mu + alpha2 + epsilon) q[t]) +
sigma3 q[t] dW3[t] + lambda3 q[t] L3[t];;
eq4 = -r'[t] + (gamma i[t] + rho s[t] + epsilon q[t] - mu r[t] -
rho s[t - tau1] Exp[-mu tau1] - gamma i[t - tau2] Exp[-mu tau2] -
epsilon q[t - tau3] Exp[-mu tau3]) + sigma4 d[t] dW4[t] +
lambda4 d[t] L4[t];
ic1 = {s[t /; t <= 0] == 5, i[t /; t <= 0] == 15, q[t /; t <= 0] == 5};
rul[j_] := {a -> A[[j]], beta -> \[Beta][[j]], rho -> \[Rho][[j]],
gamma -> \[Gamma][[j]], epsilon -> \[Epsilon][[j]],
delta -> \[Delta][[j]], alpha1 -> \[Alpha]1[[j]],
alpha2 -> \[Alpha]2[[j]], sigma1 -> \[Sigma]1[[j]],
sigma2 -> \[Sigma]2[[j]], sigma3 -> \[Sigma]3[[j]],
sigma4 -> \[Sigma]4[[j]], lambda1 -> \[Lambda]1[[j]],
lambda2 -> \[Lambda]2[[j]], lambda3 -> \[Lambda]3[[j]],
lambda4 -> \[Lambda]4[[j]], tau1 -> \[Tau]1[[j]],
tau2 -> \[Tau]2[[j]], tau3 -> \[Tau]3[[j]], mu -> mu0[[j]]};
eqn[j_] := {eq1, eq2, eq3} /. rul[j];
sol1[j_] :=
NDSolve[{eqn[j] == {0, 0, 0}, ic1}, {s, i, q}, {t, 0, tmax - 1}];
With[{sol = sol1[1]}, {Plot[Evaluate[s[t] /. {sol}], {t, 0, tmax - 1},
PlotRange -> All, Frame -> True, PlotStyle -> {Green},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["S(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18],
Plot[Evaluate[i[t] /. {sol}], {t, 0, tmax - 1}, PlotRange -> All,
Frame -> True, PlotStyle -> {Blue},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["I(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18],
Plot[Evaluate[q[t] /. {sol}], {t, 0, tmax - 1}, PlotRange -> All,
Frame -> True, PlotStyle -> {Red},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["Q(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18]}]
EDIT 2:
A (*Recruitment rate*)= {1, 0.3, 0.6, 0.6};
mu0 (*Natural mortality rate of S*)= {0.09, 0.3, 0.4, 0.4};
\[Beta] (*Transmission rate*)= {0.39, 1.3, 0.35, 0.8};
\[Gamma] (*Recovered rate*)= {0.55, 0.05, 0.2, 0.3};
\[Delta] (*Recovered rate*)= {0.44, 0.05, 0.2, 0.3};
\[Alpha]1 (*General mortality of I*)= {0.4, 0.5, 0.3, 0.3};
\[Alpha]2 (*General mortality of I*)= {0.02, 0.5, 0.3, 0.3};
\[Epsilon] (*Exponentially fading memory rate*)= {0.6, 0.09, 0.7, 0.2};
\[Rho] (*Exponentially fading memory rate*)= {0.2, 0.09, 0.7, 0.2};
\[Sigma]1 (*Intensity of W1(t)*)= {0.2, 0.15, 0.2, 0.169};
\[Sigma]2 (*Intensity of W2(t)*)= {0.4, 0.25, 0.15, 0.15};
\[Sigma]3 (*Intensity of W3(t)*)= {0.4, 0.27, 0.13, 0.13};
\[Sigma]4 (*Intensity of W4(t)*)= {0.5, 0.27, 0.13, 0.13};
\[Tau]1 (*Jump intensity of S*)= {0.5, 0.2, 0.5, 0.5};
\[Tau]2 (*Jump intensity of I*)= {0.5, 0.23, 0.3, 0.3};
\[Tau]3 (*Jump intensity of D*)= {0.5, 0.1, 0.7, 0.7};
tmax = 201; pWe1 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW1 =
Interpolation[Table[{(j - 1), pWe1[[j]]}, {j, Length[pWe1]}],
InterpolationOrder -> 1]; pWe2 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW2 =
Interpolation[Table[{(j - 1), pWe2[[j]]}, {j, Length[pWe2]}],
InterpolationOrder -> 1];
pWe3 = RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1,
1]]; dW3 =
Interpolation[Table[{(j - 1), pWe3[[j]]}, {j, Length[pWe3]}],
InterpolationOrder -> 1]; pWe4 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW4 =
Interpolation[Table[{(j - 1), pWe4[[j]]}, {j, Length[pWe4]}],
InterpolationOrder -> 1];
pL1 = RandomFunction[PoissonProcess[1.], {0, tmax}];
pL2 = RandomFunction[PoissonProcess[1.1], {0, tmax}];
pL3 = RandomFunction[PoissonProcess[1.1], {0, tmax}];
pL4 = RandomFunction[PoissonProcess[.9], {0, tmax}];
ListStepPlot[{pL1, pL2, pL3, pL4}];
dpL1 = pL1["SliceData", Range[tmax]] // First // Differences;
dpL2 = pL2["SliceData", Range[tmax]] // First // Differences;
dpL3 = pL3["SliceData", Range[tmax]] // First // Differences;
dpL4 = pL4["SliceData", Range[tmax]] // First // Differences;
L1[t_] := If[t < 1, 0, dpL1[[Round[t]]]]/tmax;
L2[t_] := If[t < 1, 0, dpL2[[Round[t]]]]/tmax;
L3[t_] := If[t < 1, 0, dpL3[[Round[t]]]]/tmax;
L4[t_] := If[t < 1, 0, dpL4[[Round[t]]]]/tmax;
eq1 = -s'[t] + (a - (mu + rho) s[t] - beta s[t] i[t] +
rho s[t - tau1] Exp[-mu tau1] + gamma i[t - tau2] Exp[-mu tau2] +
epsilon q[t - tau3] Exp[-mu tau3]) + sigma1 s[t] dW1[t];
eq2 = -i'[t] + (beta s[t] i[t] - (mu + alpha1 + delta + gamma) i[t]) +
sigma2 i[t] dW2[t];
eq3 = -q'[t] + (delta i[t] - (mu + alpha2 + epsilon) q[t]) +
sigma3 q[t] dW3[t]; eq4 = -r'[t] + (gamma i[t] + rho s[t] +
epsilon q[t] - mu r[t] - rho s[t - tau1] Exp[-mu tau1] -
gamma i[t - tau2] Exp[-mu tau2] -
epsilon q[t - tau3] Exp[-mu tau3]) + sigma4 d[t] dW4[t];
eq1o = -s'[t] + (a - (mu + rho) s[t] - beta s[t] i[t]) +
sigma1 s[t] dW1[t];
eq2o = -i'[
t] + (beta s[t] i[t] - (mu + alpha1 + delta + gamma) i[t]) +
sigma2 i[t] dW2[t];
eq3o = -q'[t] + (delta i[t] - (mu + alpha2 + epsilon) q[t]) +
sigma3 q[t] dW3[t]; eq4o = -r'[t] + (gamma i[t] + rho s[t] +
epsilon q[t] - mu r[t]) + sigma4 d[t] dW4[t];
eq1d = -s'[t] + (a - (mu + rho) s[t] - beta s[t] i[t] +
rho s[t - tau1] Exp[-mu tau1] + gamma i[t - tau2] Exp[-mu tau2] +
epsilon q[t - tau3] Exp[-mu tau3]);
eq2d = -i'[
t] + (beta s[t] i[t] - (mu + alpha1 + delta + gamma) i[t]);
eq3d = -q'[t] + (delta i[t] - (mu + alpha2 + epsilon) q[t]);
eq4d = -r'[t] + (gamma i[t] + rho s[t] + epsilon q[t] - mu r[t] -
rho s[t - tau1] Exp[-mu tau1] - gamma i[t - tau2] Exp[-mu tau2] -
epsilon q[t - tau3] Exp[-mu tau3]);
ic1 = {s[t /; t <= 0] == 10, i[t /; t <= 0] == 0.1,
q[t /; t <= 0] == 0.1};
rul[j_] := {a -> A[[j]], beta -> \[Beta][[j]], rho -> \[Rho][[j]],
gamma -> \[Gamma][[j]], epsilon -> \[Epsilon][[j]],
delta -> \[Delta][[j]], alpha1 -> \[Alpha]1[[j]],
alpha2 -> \[Alpha]2[[j]], sigma1 -> \[Sigma]1[[j]],
sigma2 -> \[Sigma]2[[j]], sigma3 -> \[Sigma]3[[j]],
sigma4 -> \[Sigma]4[[j]], tau1 -> \[Tau]1[[j]],
tau2 -> \[Tau]2[[j]], tau3 -> \[Tau]3[[j]], mu -> mu0[[j]]};
eqn1[j_] := {eq1, eq2, eq3} /. rul[j];
eqn2[j_] := {eq1d, eq2d, eq3d} /. rul[j];
sol1[j_] :=
NDSolve[{eqn1[j] == {0, 0, 0}, ic1}, {s, i, q}, {t, 0, tmax - 1},
MaxSteps -> 10^6];
sol2[j_] :=
NDSolve[{eqn2[j] == {0, 0, 0}, ic1}, {s, i, q}, {t, 0, tmax - 1},
MaxSteps -> 10^6];
With[{sol = sol1[1],
sol2 = sol2[1]}, {Plot[
Evaluate[s[t] /. {sol, sol2}], {t, 0, tmax - 1}, PlotRange -> All,
Frame -> True, PlotStyle -> {Green, Black},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["S(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18,
PlotLegends ->
Placed[LineLegend[{Green, Black}, {"S(t) with delays",
"S(t) without noise"}, LegendFunction -> Framed], {.8, .75}]],
Plot[Evaluate[i[t] /. {sol, sol2}], {t, 0, tmax - 1},
PlotRange -> All, Frame -> True, PlotStyle -> {Blue, Black},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["I(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18,
PlotLegends ->
Placed[LineLegend[{Blue, Black}, {"I(t) with delays",
"I(t) without noise"}, LegendFunction -> Framed], {.8, .75}]],
Plot[Evaluate[q[t] /. {sol, sol2}], {t, 0, tmax - 1},
PlotRange -> All, Frame -> True, PlotStyle -> {Red, Black},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["Q(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18,
PlotLegends ->
Placed[LineLegend[{Red, Black}, {"Q(t) with delay",
"Q(t) without noise"}, LegendFunction -> Framed], {.8, .75}]]}]
EDIT 3:
As mentioned in the comments of Alex's answer, when we simulate this paper: https://www.researchgate.net/profile/Dianli-Zhao/publication/332241627_Threshold_dynamics_of_the_stochastic_epidemic_model_with_jump-diffusion_infection_force/links/5ca85d24a6fdcca26d013e72/Threshold-dynamics-of-the-stochastic-epidemic-model-with-jump-diffusion-infection-force.pdf, our plots, although similar, do not show the effects of Levy noise as what paper shows, any idea why?
The code for new paper:
µ(*Natural mortality rate of S,I,*)= {0.05, 0.05, 0.05, 0.4};
\[Beta] (*Transmission rate*)= {0.3, 0.3, 0.3, 0.8};
\[Delta](*Transmission rate*)= {0.05, 0.05, 0.05, 0.8};
\[Gamma] (*Recovered rate*)= {0.1, 0.1, 0.1, 0.3};
\[Sigma]1 (*Intensity of W1(t)*)= {0.1, 0.1, 0, 0.169};
\[Lambda]1 (*Intensity of W2(t)*)= {0.2, 0, 0, 0.15};
tmax = 801; pWe1 =
RandomFunction[WhiteNoiseProcess[], {0, tmax}][[2, 1, 1]]; dW1 =
Interpolation[Table[{(j - 1), pWe1[[j]]}, {j, Length[pWe1]}],
InterpolationOrder -> 1];
pL1 = RandomFunction[PoissonProcess[1], {0, tmax}];
ListStepPlot[{pL1}];
dpL1 = pL1["SliceData", Range[tmax]] // First // Differences;
L1[t_] := If[t < 1, 0, dpL1[[Round[t]]]]/tmax;
eq1 = -s'[t] + (mu - mu s[t] - beta s[t] i[t]) -
sigma1 s[t] i[t] dW1[t] + lambda1 L1[t];
eq2 = -i'[t] + (beta s[t] i[t] - (mu + delta + gamma) i[t]) +
sigma1 s[t] i[t] dW1[t] + lambda1 L1[t];
ic = {s[0] == 0.5, i[0] == 0.1};
rul[j_] := {beta -> \[Beta][[j]], gamma -> \[Gamma][[j]],
mu -> µ[[j]], delta -> \[Delta][[j]], sigma1 -> \[Sigma]1[[j]],
lambda1 -> \[Lambda]1[[j]]};
eqn[j_] := {eq1, eq2} /. rul[j];
sol[j_] := NDSolve[{eqn1[j] == {0, 0}, ic}, {s, i}, {t, 0, tmax - 1}];
With[{sol = sol[1], sol2 = sol[2],
sol3 = sol[3]}, {Plot[
Evaluate[s[t] /. {sol, sol2, sol3}], {t, 0, tmax - 1},
PlotRange -> All, Frame -> True, PlotStyle -> {Red, Black, Blue},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["S(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18, FrameStyle -> Black,
PlotLegends ->
Placed[LineLegend[{Red, Black, Blue}, {"With jumps",
"without jumps", "Deterministic"},
LegendFunction -> Framed], {.85, .85}]],
Plot[Evaluate[i[t] /. {sol, sol2, sol3}], {t, 0, tmax - 1},
PlotRange -> All, Frame -> True, PlotStyle -> {Red, Black, Blue},
FrameLabel -> {Style["Time(Days)", 20, Black],
Style["I(t)", 20, Black]}, ImageSize -> 500,
FrameTicksStyle -> 18, FrameStyle -> Black,
PlotLegends ->
Placed[LineLegend[{Red, Black, Blue}, {"With jumps",
"without jumps", "Deterministic"},
LegendFunction -> Framed], {.8, .8}]]}]