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I developed a Mathematica package using Mathematica 12.1 and I am calling this package from my java code: I generate a system of equations (where I call the package) from the java code, then send this system to the Mathematica Kernel to solve it, but it takes at least 2 or 3 minutes to return a result (and sometimes keeps running). When I run Mathematica front end to solve the same system, it takes few microseconds. Can anyone tell me why is Mathematica Kernel is extremely slow?

thanks a lot

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    $\begingroup$ Welcome to the Mathematica Stack Exchange. Tell us more about your Java setup and how you are invoking the kernel. Have you followed an(y) example from a tutorial that worked better etc. Thanks. $\endgroup$
    – Syed
    Sep 17, 2022 at 10:46
  • $\begingroup$ I am working with Intellij Idea and use jlink, this is the java code where I create a connection with Mathematica then call Mathematica Kernel : KernelLink ml; String s = "-linkmode launch -linkname 'C:\\Program Files\\Wolfram Research\\Mathematica\\12.1\\MathKernel.exe'"; ml = MathLinkFactory.createKernelLink(s); ml.connect(); ml.discardAnswer(); String res = ml.evaluateToInputForm(exp,0); //exp=<<MyPackage;UsingFrontEnd[MyPackageFunc[]] $\endgroup$
    – W.G
    Sep 17, 2022 at 19:26
  • $\begingroup$ No I am not following any tutorial. thanks a lot! $\endgroup$
    – W.G
    Sep 17, 2022 at 19:27
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    $\begingroup$ Can you share some examples of the code in the package? $\endgroup$ Sep 20, 2022 at 9:48

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For those who are interested, I could finally solve the problem by simply sending two seperate commands to Mathematica kernel from my java code: in the first command I evaluate the call to my package, and in the second command, I evaluate the system of equations (that uses my package). So instead of send one command of the form:

ml.evaluateToOutputForm(<<Mypackage`;systemOfEquationsToSolve) 

I send the following two commands:

ml.evaluateToOutputForm("<<MyPackage`");
ml.discardAnswer();
ml.evaluateToOutputForm(systemOfEquationsToSolve);
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    $\begingroup$ If the function f is define in SomePackage, then a combined (Get["SomePackage`"]; f[]) is not equivalent to evaluating these two commands separately. The package must be loaded before f[] is parsed (note: parsed, not merely evaluated). Otherwise f will be interpreted in the Global context, not in your package's context. $\endgroup$
    – Szabolcs
    Nov 20, 2022 at 12:25

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