1
$\begingroup$

I would like to take the derivative of the absolute-squared value of a hypergeometric function and plot the result, for real arguments

D[ComplexExpand[Conjugate[Hypergeometric2F1[I s, I p, 1, x]]Hypergeometric2F1[I s, I p, 1, x]], x]

but the result is given in terms of the undefined function

Im'

I thought that ComplexExpand is supposed to be used to avoid this problem, it helps with some simple functions (like Sin[x]) but not with 2F1. Is there a better way to plot the derivative? Note s,p,x are real.

$\endgroup$
1
  • 4
    $\begingroup$ Generally, ComplexExpand[] is not equipped to handle special functions like Hypergeometric2F1[]. In the meantime, have you already seen this? $\endgroup$ Commented Jul 2, 2022 at 20:08

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.