ListLinePlot not showing one label in a cycle of points

Question

I am using ListLinePlot to represent a closed circuit of points (forming a polyhedron). I am trying to label each node (point) of the cycle, but the node that is present twice gets no label.

This is my example:

ListLinePlot[{{11, 7}, {7, 9}, {15, 15}, {16, 12}, {11, 7}} -> {"A'", 
   "B'", "C'", "D'", " "}, 
 LabelingFunction -> 
  Callout[Automatic, Automatic, Appearance -> None], 
 Filling -> Bottom, AspectRatio -> Automatic, 
 PlotRange -> {{0, 20}, {0, 20}}, AxesLabel -> {"z1", "z2"}, 
 Mesh -> Full, 
 GridLines -> Function[{min, max}, Range[Floor[min], Ceiling[max]]]]

This is the result I get:

I think the problem is with point {11, 7} (that should be labelled with "A'"), which appears twice in the main argument of the function ListLinePlot. I tried different approaches, but nothing seemed to work.

Any assistance will be appreciated.

Answer 1

Since you don't seem to want the stem / leader feature from Callout, try LabelingFunction -> Labeled instead. The results are practically identical to what you show in your answer:

ListLinePlot[
  {{11, 7}, {7, 9}, {15, 15}, {16, 12}, {11, 7}} -> {"A'", "B'", "C'", "D'", ""},

  LabelingFunction -> Labeled, 

  Filling -> Bottom,
  AspectRatio -> Automatic,
  PlotRange -> {{0, 20}, {0, 20}},
  AxesLabel -> {"z1", "z2"},
  Mesh -> Full, 
  GridLines -> Function[{min, max}, Range[Floor[min], Ceiling[max]]]
]

Answer 2

I found a way, using Show, which allows overlaying different plots:

Show[
 ListLinePlot[{{11, 7}, {7, 9}, {15, 15}, {16, 12}, {11, 7}} -> {"A'",
     "B'", "C'", "D'", "-"}, 
  LabelingFunction -> 
   Callout[Automatic, Automatic, Appearance -> None], 
  Filling -> Bottom, AspectRatio -> Automatic, 
  PlotRange -> {{0, 20}, {0, 20}}, AxesLabel -> {"z1", "z2"}, 
  Mesh -> Full, 
  GridLines -> Function[{min, max}, Range[Floor[min], Ceiling[max]]]],
 ListLinePlot[{{11, 7}} -> {"A'"}, 
  LabelingFunction -> 
   Callout[Automatic, Automatic, Appearance -> None], 
  PlotRange -> {{0, 20}, {0, 20}}]
 ]

I get this:

Anyway, I think a solution without using the Show hack should be possible.