# Please I need help to define a function of two variables (t,x)!

Let's define the following function:

f[t_, x_] = t^2 + t*x*(1 - x)


such that $$x \in (0,1)$$ and $$t \in (0,0.02)$$ The problem is when I want to define the following function:

z[t_,x_] = Interpolation[Table[{x, f[t, x] Piecewise[{{1, 0.2 < x < 0.8}}]}, {t, 0,0.02},{x, 0,1, 1/24}]];


This is not working!! (I think the problem is because I discretize in space and not in time!!)

• I'm not familiar with your goal but here are a couple of notes you probably missed: _ for arguments in defining f, using = instead of := in defining z, and also when you don't specify step in Table it's 1 which in your case t has almost no effect. Running Table alone will show you it will return a nested list not the kind of input Interpolation wants. Another thing is using similar names (z and Table). I think I should also remind using ClearAll before correcting the notes. Apr 1 at 11:44
• You have right, the problem is that I get a list not the kind of input Interpolation wants. and I don't know how to solve this problem, I need a way to define a function of two parameters, t and x such that ${t, 0, 0.02}$ and ${x, 0,1, 1/24}$!! I don't know how!! Apr 1 at 12:09

I'm not 100% clear what you are trying to achieve. If you want to sample your continuous function $$f(t,x)$$ at only discrete values of $$x$$, but be able to call it later for any value of $$t$$ then:

f[t_,x_]:= (t^2 + t x (1-x)) Piecewise[{{1,0.2<x<0.8}}];


which we can sample then using:

zdis[t_]:= Table[f[t,x],{x,0,1,1/24}];


You can plot all values then using:

Plot[Evaluate[zdis[t]],{t,0,0.04},PlotLabels-> Table[InputForm[x], {x, 0, 1, 1/24}]]


giving: To get the $$i$$th value where $$x = i/24$$ for $$i\in [0,24]$$ you can either just call

zdis[t][[i+1]]


or build this into the original definition as per:

zdis[t_,i_?IntegerQ]:= f[t,i/24];


where the ?IntegerQ requires the input to be an integer.

• thank you, this is exactly what I'm looking for, I just need a little more detail please. after you define the table $zdis[t_]$, can you please show me how I can define a new function $g(t , i)$ such that for each value of $t \in (0,0.02)$ and $i \in (0,1/24,1/12,....,1)$ I get the value !! Apr 1 at 17:58
• See the addendum to the answer. Note that the $i$ input in my answer is an integer, not a multiple of 1/24, which is harder to do (and unnecessay). Defining this secondary function zdis is not really necessary in the first place if you only ever call f[t,x] with values of $x \in [0,1/24,2/24,....]$. Apr 1 at 18:38

Perhaps FunctionInterpolationis what you're looking for.

Try

f[t_, x_] = t^2 + t*x*(1 - x)
fip = FunctionInterpolation[f[t, x] Piecewise[{{1, 0.2 < x < 0.8}}], {t, 0, 0.02}, {x, 0, 1 }]
Plot3D[fip[t, x], {t, 0, 0.02}, {x, 0, 1}] For discrete interpolation in x we transform f[t,x] in a product {t^2,t}. {1,x(1-x).

Now it's possible to interpolate x:

ip = Interpolation[Table[{x, Piecewise[{{1, 0.2 < x < 0.8}}] {1, x (1 - x)}}, {x, 0, 1,1/24}],InterpolationOrder->1];

Plot[ip[x],{x,0,1}] Final function follows to {t^2,t}.ip[x]!

• Thank you for your answer, But I see that you consider x in the whole interval (0,1). Me I need $(x, 0,1, 1/24)$. Apr 1 at 12:13
• That means you're looking for a discrete interpolation ,{x, 0,1, 1/24}`? Apr 1 at 12:21
• that's right, I'm looking to define a discrete function in space but not in time.!! Apr 1 at 12:24
• @walidfssm See my modified answer, now with discrete interpolation x. Apr 1 at 13:20
• Thank you for your answer, But, this is not what I need. is it not possible to define it without separating it into a product!! Apr 1 at 13:49