How do I find the curvature of the vector when t=5?
The function is:
v[t_] := {2 t^4 + 2, 6 t^3 + 1, 3 t^2 + 4}
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Sign up to join this communityv[t_] := {2 t^4 + 2, 6 t^3 + 1, 3 t^2 + 4}
curv = ArcCurvature[v[t], t]
You sent t
to 5
like so:
N[curv /. t -> 5]
There's another way but I am letting this up to @cvgmt to show it
FrenetSerretSystem[v[t], t][[1,1]]/.t->5
$\endgroup$FrenetSerretSystem
and was hoping that you'd write an answer :-) $\endgroup$