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How do I find the curvature of the vector when t=5?

The function is:

    v[t_] := {2 t^4 + 2, 6 t^3 + 1, 3 t^2 + 4}
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  • $\begingroup$ Please read my comment! mathematica.stackexchange.com/questions/264624/… $\endgroup$
    – cvgmt
    Mar 4, 2022 at 4:51
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    $\begingroup$ FrenetSerretSystem[v[t], t][[1,1]]/.t->5 $\endgroup$
    – cvgmt
    Mar 4, 2022 at 4:52
  • $\begingroup$ @cvgmt as you can see from my answer, I kind of guessed the FrenetSerretSystem and was hoping that you'd write an answer :-) $\endgroup$ Mar 4, 2022 at 4:55

1 Answer 1

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v[t_] := {2 t^4 + 2, 6 t^3 + 1, 3 t^2 + 4}

curv = ArcCurvature[v[t], t]

You sent t to 5 like so:

N[curv /. t -> 5]

There's another way but I am letting this up to @cvgmt to show it

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