0
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after plotting this function:

ParametricPlot[
 With[{z = Exp[I θ]}, 
  Through[{Re, Im}[
    1 - ((I 0.8) Log[(1 - E^(-((I π 0.2)/0.8)) z)/(1 - E^((I π 0.2)/0.8) z)])/π
    ]] ],
 {θ, 0, 2 π}, ImageSize -> Medium, PlotRange -> {{-1, 1}, {-1, 1}}]

Or alternatively, after substituting in the value for z outside the plotting function:

ParametricPlot[{1 + 
   Re[(0.` - 0.25464790894703254` I) Log[(
      1 - (0.7071067811865476` - 0.7071067811865475` I) E^(I θ))/(
      1 - (0.7071067811865476` + 0.7071067811865475` I) E^(I θ))]], 
  Im[(0.` - 0.25464790894703254` I) Log[(
     1 - (0.7071067811865476` - 0.7071067811865475` I) E^(I θ))/(
     1 - (0.7071067811865476` + 0.7071067811865475` I) E^(I θ))]]}, {θ, 0, 2 π},
     ImageSize -> Medium,  PlotRange -> {{-1, 1}, {-1, 1}}]

enter image description here

I don't know what should I add to make something as a shadow to the resulting line to separate the two resulting plans. Does anyone have any suggestions?

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  • 2
    $\begingroup$ Can you please fix your code so that it plots when we copy/paste it? $\endgroup$ – bill s Jun 4 '13 at 5:12
  • $\begingroup$ yes .. that is right .. it is just a vertical line and i want to add something as a shadow to that line to separate the two halfs.. $\endgroup$ – user6921 Jun 4 '13 at 7:27
  • 1
    $\begingroup$ You might look here -- for instructions on adding dropshadows to plots mathematica.stackexchange.com/questions/3058/… $\endgroup$ – bill s Jun 4 '13 at 8:08