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I am currently trying to contourplot a dimensionless velocity-field given as:

W =  1/\[Alpha] Im[Sec[Cos[-(1/2) q I Log[10, (2 \[Alpha] \[CapitalTheta])/q]]/
 Cos[\[Alpha]]] + 1/2 I q Log[10, (2 \[Alpha] \[CapitalTheta])/q]]

with

\[Alpha] -> \[Pi]/8, q -> 1, a -> 10/10^6

and the complex polar coordinate \[CapitalTheta] -> a R E^(I \[CurlyPhi]) with {R, 0, 4/\[Pi]}, {\[CurlyPhi], 0, 2 \[Pi]} My problem now is to generate the ContourPlot of the function. I know how the result should look like (at least similar) enter image description here

I have already tried a coordinate transformation and much more, but unfortunately that did not work either.

I´d be happy for every bit of support. Thanks and best regards, Seb

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    – bbgodfrey
    Jan 26, 2022 at 13:37

1 Answer 1

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With the proper replacements, I get something different from your solution:

W = 1/\[Alpha] Im[
     Sec[Cos[-(1/2) q I Log[10, (2 \[Alpha] \[CapitalTheta])/q]]/
        Cos[\[Alpha]]] + 
      1/2 I q Log[
        10, (2 \[Alpha] \[CapitalTheta])/q]] /. {\[Alpha] -> \[Pi]/8, 
    q -> 1, \[CapitalTheta] -> a R E^(I \[CurlyPhi])} /. {a -> 
    10/10^6};

ContourPlot[W, {R, 0, 4/\[Pi]}, {\[CurlyPhi], 0, 2 \[Pi]}, 
 FrameLabel -> {"X", "Y"}]

enter image description here

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  • $\begingroup$ Hey, without transforming the polar coordinates into cartesian coordinates, I get the same result as you. $\endgroup$
    – SebZ
    Jan 26, 2022 at 14:16

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