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I'm trying to calculate

Sum[(1/n)^(n), {n, 1, Infinity}]

But mathematica outputs the input directly. What is the problem? when I put the same expression into wolframalpha, it gives me the answer but not mathematica.

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    $\begingroup$ Use NSum in Mathematica to get a numerical approximation. $\endgroup$
    – Daniel Lichtblau
    Nov 6, 2021 at 15:09

1 Answer 1

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Mathematica Sum just returns input means MMA doesn't find an analytical answer

The sum seems to be convergent

SumConvergence[(1/n)^(n), n]
(* True *)

Numerically result

NSum[(1/n)^(n), {n, 1, Infinity}]
(*1.29129*)

That's the result from WolframAlpha!

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