5
$\begingroup$

I have a list called matcoeffE which has dimensions {10, 9, 7, 2}. However, I want to build a matrix with dimensions {180,7} and then export it as an Excel file. At the first step I used:

newmat = FlattenAt[matcoeffE, Transpose[{Range[10]}]];

so dimensions of newmat became {90, 7, 2}. After that I have to flatten 2 (2*90) and get a new matrix which has dimensions {180,7} which produces an Excel file with 190 rows and 7 columns (in a single sheet). My mean is: newmat has 90 rows and 7 columns which each column has two numbers in it. I want to second number of each this two-member list goes to the next row (namely each second member is placed under the first member), so that the dimensions will be {180,7}. I tried to show my mean schematically as follows:

Enter image description here

I tried Splice for example, but it didn't work. In fact I always have a problem with flattening the nested list. How can I solve my problem? Is there a simple and general way to flatten nested lists?

$\endgroup$
3
  • 1
    $\begingroup$ To do the first part, you could use newmat = ArrayReshape[matcoeffE, {90, 7, 2}]; but I do not understand the rest of your question now. $\endgroup$
    – Nasser
    Commented Oct 24, 2021 at 9:10
  • $\begingroup$ @Nasser See my updates $\endgroup$
    – Wisdom
    Commented Oct 24, 2021 at 9:25
  • $\begingroup$ What do you mean by "my mean"? $\endgroup$ Commented Oct 24, 2021 at 19:17

1 Answer 1

15
$\begingroup$

Code is the best illustration

a = RandomReal[{0, 1}, {10, 9, 7, 2}];
Dimensions[a]
(*{10, 9, 7, 2}*)

b = Transpose[a, {1, 2, 4, 3}];
Dimensions[b]
(*{10, 9, 2, 7}*)

c1 = Flatten[b, 1];
Dimensions[c1]
(*{90, 2, 7}*)

c2 = Flatten[b, 2];
Dimensions[c2]
(*{180, 7}*)

One can do everything at once

c3 = Flatten[a, {{1, 2, 4}, {3}}];
Dimensions[c3]
(*{180, 7}*)

And verify

Norm[c3 - c2]
(* 0 *)

Explanations

There are some differences between Transpose and Flatten that one needs to take care of.

  • If you write b = Transpose[a, {1, 2, 4, 3}] it means that the 3rd dimension of a will become the 4th dimension of b. That is, {1, 2, 4, 3} denotes the destination of dimensions.
  • Let the second argument of Flatten be n. n+1 tells you how many dimensions starting from the first one will be combined together. This means Flatten[b, 2] combines 3 first dimensions into one.
  • Flatten with a 2nd argument being a list is slightly different: Flatten[a, {{1, 2, 4}, {3}}] means combine dimensions 1, 2 and 4 into the first dimension, combine dimension 3 into the second dimension. And so on. As you can see this is very flexible as it allows to transpose and flatten at the same time.
$\endgroup$
4
  • 1
    $\begingroup$ Thank you soooooo much, can you add some explanations to your answer? I really need to understand the way Flatten works, for example how you build c3 in one step? $\endgroup$
    – Wisdom
    Commented Oct 24, 2021 at 10:11
  • $\begingroup$ @Wisdom Yes, see the edits $\endgroup$
    – yarchik
    Commented Oct 24, 2021 at 10:29
  • $\begingroup$ Good job and great trick! However I need to practice it to understand deeply. Thanks again. $\endgroup$
    – Wisdom
    Commented Oct 24, 2021 at 10:33
  • 3
    $\begingroup$ @Wisdom see also Flatten command: matrix as second argument $\endgroup$
    – WReach
    Commented Oct 24, 2021 at 18:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.