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Short answer: Subscript[a,0] =.
(That's Unset
in the docs.)
Long answer: and, well, although it's actually kind of a non-answer, my genuine advice here is: don't use subscripted variables in the first place, since they're pretty finicky. Instead use a[0]
, a[1]
, etc.
For one, you'll notice that a
in your code is blue, not black, meaning there are no definitions associated with it. The definitions you've made have actually gotten attached to the symbol Subscript
, so you'd have to either Clear[Subscript]
to clear all subscripted values, or use Subscript[a,0] =.
Since every expression in Mathematica is either an atom or of the form f[a, b, c, ...]
(stuff that seems like it isn't is, most often, just syntactic sugar), using a[i]
is generally a lot more compatible with the rest of mathematica and therefore easier to code with. Consider Array[a, 3]
which gets you {a[1], a[2], a[3]}
; there are many more examples.
If you want to use this, but still want it to look like a subscript, you can use
Format[a[i_]] := Subscript[a, i]
and it will print as a subscript in output expressions.
Of course, if you're just doing one or two things, there's no problem using Subscript
! But if you're doing a lot it can get a bit frustrating, and might be easier to use this structure.
I wanted to leave this as a comment, since it's more just "best practices" stuff than an answer per se, but it was too long, so here you go :)