I have the following data
setA = {{0.0001, 0.5, 0.5000000020621443`}, {0.01,
0.9090909090909091`, 0.9089263228218556`}, {0.1,
0.9803921568627451`, 0.9685612823447454`}, {1,
0.9951923076923077`, 0.8965347385041562`}, {10,
0.9975062344139651`, 0.8370285555286358`}, {1000,
0.9988901220865705`, 0.809761243637952`}, {10000,
0.9994556341861731`, 0.8080295675491966`}};
setB = {{0.0001, 0.5, 1.1754907046612933`*^-8}, {0.01,
0.9090909090909091`, 0.0001497516481925709`}, {0.1,
0.9803921568627451`, 0.013113265479399906`}, {1,
0.9951923076923077`, 0.36837218815129213`}, {10,
0.9975062344139651`, 4.605802823908744`}, {1000,
0.9988901220865705`, 495.77609116353705`}, {10000,
0.9994556341861731`, 4985.705218556087`}};;
which has the form $ \{\omega, \mu , a \}$ for setA and $ \{\omega, \mu , b \}$ for setB. Now I want to fit setA to $$ \mu \Bigl(a_1-a_2 \text{erf}(\text{Log}[\omega]\sqrt{a_3 \mu})\Bigl) $$ and fit setB to $$ \lvert -b_1 \text{exp}\bigl( b_2 \text{Log}[\omega]\mu+ \frac{\mu \omega}{2} \bigr) \rvert $$ I tried these following codes
fitA = NonlinearModelFit[
setA, \[Mu] (a1 - a2 Erf[Log[\[Omega]] Sqrt[a3 \[Mu]]]), {a1, a2,
a3}, {\[Mu], \[Omega]}]
and
fitB = NonlinearModelFit[setA,
Abs[-b1 Exp[b2 Log[\[Omega]]] \[Mu] + (b3 \[Mu] \[Omega])/2], {b1,
b2, b3}, {\[Mu], \[Omega]}]
but they don't work specially for setA. It returns this error:
NonlinearModelFit::nrlnum: The function value {-0.499987023189+0.0354938976555 I,-0.907628435515+5.02574192093 I,-0.955582409275+31.8756408087 I,-0.766746007804+242.692381728 I,0.46085875147 +4082.71039099 I,128.978969456 +5.26288648114*10^6 I,1297.07927743 +9.21370092281*10^8 I} is not a list of real numbers with dimensions {7} at {a1,a2,a3} = {0.1297887307,987.212217384,-1981.56646201}.
Any idea to fit my data to formula?
Addendum
I have determined the values of all these parameters using a two-step fitting (first, fit to $\omega$ and then fit to $\mu$). They have the following values which match to my real data:
$$ a_1=0.9,\; a_2=0.096,\; a_3=1.333,\; b_1=0.1,\; b_2=0.5 $$
but I want to reproduce them using a one-step fitting to make sure my results were true. In fact this is a cross-checking.
setA
? Is your "2-step fitting" a recognized fitting technique? $\endgroup$