I want to obtain the Laurent of the function f(z) = 1/(z(z-1))
valid first in 0 < Abs[z] < 1
and second in Abs[z] > 1
. I tried
Series[f[z], {z, 0, 4}, Assumptions -> (0 < Abs[z] < 1)]
obtaining the correct result, but when I change the Assumptions
Series[f[z], {z, 0, 4}, Assumptions -> Abs[z] > 1]
I obtain the same result, which is wrong. What am I doing wrong?
Series[1/(z*(z - 1)), {z, Infinity, 4}]
. $\endgroup$