I've read some article recently and because I've been doing the same calculations so far, I wanted to have a graph like this: enter image description here

by the looks of it, it certainly looks like it was done in mathematica, as you can see at each natural number n, it is split into 3 domains for the different colors, this is very useful as it shows the interference.

  • $\begingroup$ does this answer give what you need? $\endgroup$
    – kglr
    Jun 23, 2021 at 23:23

1 Answer 1


BarChart accepts lists of lists; each sublist is a single datapoint from each data set. For instance BarChart@Table[{i,i,i},{i,20}] gives


So a rough attempt at that chart is

BarChart[{(8^# E^-8)/#!,(12^# E^-12)/#!,(16^# E^-17)/#!}&/@Range@30,


In my mind there are two ways to refine this to make it "right": get the data right, and get the style right.

If you have the equations, getting the data right is easy. If not, it's surprisingly easy to derive the data from the image (with Mathematica). It may even be useful to do curve fitting (which is, again, easy with Mathematica).

Matching the above style is hard. Here's some options that need to be specified (I don't know exactly how to do them)

  • bar black outlines
  • spacing between bar triplets
  • ticks along entire frame
  • ticks are in the style of a graph (not divisions between bars, but axes)
  • font

Hopefully you can go from here!

  • $\begingroup$ the problem with barcharts is that they don't start from 0 in the conventional x axis, is there any way to get around this? $\endgroup$ Jun 23, 2021 at 22:51
  • $\begingroup$ If you want to stick with bar chart labels it's easy; wrap each datum in a Labeled with the appropriate number. It looks like BarChart isn't the best way to do this, though; see mathematica.stackexchange.com/questions/198975/…. Probably removing the bottom ticks a la Carl Woll's answer and Showing a Plot along with is better $\endgroup$
    – Adam
    Jun 24, 2021 at 0:34

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