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I have asked this question previously and I didn’t get a satisfactory answer. Then I posted a comment and didn’t receive any replies. So I thought to elaborate my issue. I have:

Plot[{Sin[t]^2}, {t, 0, 3000}, Background -> White]

Then I get cc

Plot[{Sin[t]^2}, {t, 0, 3000}, Background -> White, Ticks -> {{#, 1/902*Pi/4 #} & /@ FindDivisions[{0., 3000}, 6] // N, Automatic}]

Then I get: bhj

When you compare two figures, I rescaled the x axis in second figure without altering y axis with new ticks. But actually when you look you can see that second plot can be written in terms of Pi multiples. But I don’t know how. Any way?

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  • $\begingroup$ Just remove // N? $\endgroup$
    – kglr
    May 31, 2021 at 11:30
  • $\begingroup$ @kglr That’s great. But it not as standard notation as 0,Pi/4,Pi/2,3pi/4 , Pi! $\endgroup$
    – Jasmine
    May 31, 2021 at 11:48
  • $\begingroup$ does Ticks -> {Transpose[{Rescale[#, {0, Pi}, {0, 3000}], #} &@ FindDivisions[{0, Pi, Pi/16}, 8, Method -> {}]], Automatic} give what you need? $\endgroup$
    – kglr
    May 31, 2021 at 11:57
  • $\begingroup$ @kglr It’s working. But I am not sure where did you incorporate 1/902*Pi/4. $\endgroup$
    – Jasmine
    May 31, 2021 at 12:06
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    $\begingroup$ if you want the horizontal range to go from 0 to 3000 Pi /902/4 (as x goes from 0 to 3000) try Ticks -> {Transpose[{Rescale[#, {0, 3000 Pi/902/4}, {0, 3000}], #} &@ FindDivisions[{0, 3000 Pi/902/4, Pi/16}, 8, Method -> {}]], Automatic} $\endgroup$
    – kglr
    May 31, 2021 at 12:29

1 Answer 1

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xticks = Transpose[{4 # 902 / Pi, #}] &@
  FindDivisions[{0, 3000 Pi/902/4, Pi/16}, 8, Method -> {}]

Plot[Sin[t]^2, {t, 0, 3000}, Ticks -> {xtikcs, Automatic}]

enter image description here

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