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Given this Matrix

{{0, 0, 0, 0}, {1, 2, 92.355, 49.}, {1, 7, 86.7407, 46.5}, {6, 2, 
  92.355, 49.}, {6, 7, 87.237, 46.5}}

How can I automatically access the third column entry in the row where the first entry is 1 and the second is 7 (86.7407)?

This automatisation really should look at the first two entries of the rows and then give back the third column number in that row.

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2 Answers 2

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Try

m={{0,0,0,0},{1,2,92.355,49.},{1,7,86.7407,46.5},{6,2,92.355,49.},{6,7,87.237,46.5}};
Cases[m,{1,7,__}][[1,3]]

which should return 86.7407

The Cases with that pattern will find all rows matching the first two elements and then the [[1,3]] will extract the third element from the first matching row.

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  • $\begingroup$ Thank you Roman and Bill! $\endgroup$
    – user34047
    May 9, 2021 at 14:04
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data = {{0, 0, 0, 0}, {1, 2, 92.355, 49.}, {1, 7, 86.7407, 46.5},
        {6, 2, 92.355, 49.}, {6, 7, 87.237, 46.5}};

FirstCase[data, {1, 7, x_, ___} -> x]
(*    86.7407    *)
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